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Lelu [443]
3 years ago
7

Which element is a metalloid? selenium (Se) germanium (Ge) phosphorus (P) iodine (I)

Chemistry
2 answers:
sergij07 [2.7K]3 years ago
9 0

Answer:

Ge

Explanation:

Edge 2021

paisleigh
3 years ago
thank you
LiRa [457]3 years ago
6 0

Answer:

Ge

Explanation:

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Diffusion is a type of active transport
Rudiy27

Answer:

True

Explanation:

Diffusion is an active process that requires a cell to expand a great deal of energy. ... Diffusion through ion channels is a form of active transport. False. Passive transport uses ATP to move molecules against their concentration gradient.

4 0
3 years ago
An example of a solid solution is copper true or false
garik1379 [7]
This is false, because copper is an element.
To be solution, it has to have at least 2 different substances. Solid solution of metals is often called alloy. 
4 0
4 years ago
Qual substância apresenta 2 (dois) pares de elétrons sendo compartilhados entre seus átomos na
-Dominant- [34]

Answer:

Explanation:

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3 0
3 years ago
4g of sugar is dissolved in 46 g of water calculate the concentration as percent by mass
Lina20 [59]
The  concentration as  %  by  mass  is  calculated as below

mass  of  solute/mass of  solvent x100
mass of  solute(sugar) = 4g
mass of   solvent(water) =46  g

= 4g/  46 g x100 = 8.7%
3 0
3 years ago
Read 2 more answers
An aqueous nacl solution is made using 112 g of nacl diluted to a total solution volume of 1.00 l. calculate the molarity, molal
worty [1.4K]
Q1)
molarity is defined as the number of moles of solute in 1 L of solution.
the NaCl solution volume is 1.00 L
number of moles NaCl  = NaCl mass present / molar mass of NaCl 
NaCl moles = 112 g / 58.5 g/mol = 1.91 mol 
the number of moles of NaCl in 1.00 L of solution is - 1.91 mol 
therefore molarity of NaCl is 1.91 M

Q2) 
molality is defined as the number of moles of solute in 1 kg of solvent.
density is mass per volume. 
density of the solution is 1.08 g/mL. 
therefore mass of the solution is = density x volume 
mass = 1.08 g/mL x 1000 mL = 1080 g
since we have to find the moles in 1 kg of solvent 
mass of solvent = 1080 g - 112 g = 968 g
number of moles of NaCl in 968 g of solvent - 1.91 mol 
therefore number of NaCl moles in 1000 g - (1.91 mol / 968 g) x 1000 g/kg = 1.97 mol/kg
molality of NaCl solution is 1.97 mol/kg


Q3) 
mass percentage is the percentage of mass of solute by total mass of the solution 
mass percentage of solution = mass of solute / total mass of the solution 
mass of solute = 112 g
total mass of solution = 1080 g
mass % of NaCl = 112 g / 1080 g x 100%
therefore mass % of NaCl = 10.4 %
answer is 10.4 %
5 0
3 years ago
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