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FrozenT [24]
3 years ago
11

Please help. 5. Give an example of an open equation. (1 point)

Mathematics
2 answers:
Sergio [31]3 years ago
7 0

Answer:

hiiiii

Step-by-step explanation:

Papessa [141]3 years ago
5 0

Answer:

x+4 = 8

(❁´◡`❁)(❁´◡`❁)(❁´◡`❁)

Step-by-step explanation:

An example would be x+4 = 8

(❁´◡`❁)(❁´◡`❁)(❁´◡`❁)

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What is the probability that 1 or 2 are rolled on a number cube with sides numbered 1, 2, 3, 4,
choli [55]

Answer: \frac{1}{3}

Step-by-step explanation:

total sides = 6

p (rolling a 1) = \frac{1}{6}

p (rolling a 2) = \frac{1}{6\\}

Note:

or - add

and - multiply

∴ \frac{1}{6} +\frac{1}{6} = \frac{2}{6}

∴ \frac{2}{6} = \frac{1}{3}

hence, p (rolling a 1 or 2) = \frac{1}{3}

4 0
3 years ago
In Exercises 5 and 6, find each missing length.
stira [4]

Answer:

6.21.4

Step-by-step

6 0
3 years ago
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In humans, which set of chromosomes do males have?<br> Ο Α. ΥΥ<br> OOO<br> O D. XYY
Kisachek [45]
Males have chromosome pairs of (XY) and Females have chromosome pairs of (XX)
4 0
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4 0
3 years ago
In a survey of 1000 large corporations, 260 said that, given a choice between a job candidate who smokes and an equally qualifie
Usimov [2.4K]

Answer:

The 95% confidence interval for the proportion of corporations preferring a nonsmoking candidate is (0.2328, 0.2872)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 1000, p = \frac{260}{1000} = 0.26

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.26 - 1.96\sqrt{\frac{0.26*0.74}{1000}} = 0.2328

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.26 + 1.96\sqrt{\frac{0.26*0.74}{1000}} = 0.2872

The 95% confidence interval for the proportion of corporations preferring a nonsmoking candidate is (0.2328, 0.2872)

4 0
3 years ago
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