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3 years ago

Greatest common factor 16, and 24

Mathematics

2 answers:

kupik [55]3 years ago

7 0

$\large\text{Hey there!}$

$\large\text{Greatest common factor (GCF) of 16 \& 24}$

$\large\text{16: 1, 2 , 4 , 8 , \& 16}$

$\large\text{24: 1 , 2 , 3 , 4 , 6 , 8 , 12 , \& 24}$

$\large\text{Like terms of both of your numbers: 1, 2, 4, \& 8}$

$\large\text{The GREATEST out of like terms is: 8}$

$\boxed{\boxed{\large\text{Thus, your answer is :\boxed{\large\text{\bf{Your Greatest Common Factor is: \underline{8}}}}}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\dfrac{\frak{LoveYourselfFirst}}{:)}$

statuscvo [17]3 years ago

6 0

Answer:

The answer is 8. :D Hope this helps!

Explanation Edit: The greatest common factor is 8. Out of all the like terms, 1, 2, 4, and 8, 8 is the greatest. The greatest term is 8 = The greatest common factor. 8 is the greatest common factor.

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Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Veronika [31]

The expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Given an integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ .

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

$\int\limits^b_a {f(x)} \, dx$ = $\lim_{n \to \infty}$ ∑f(a+iΔx)Δx ,here Δx=(b-a)/n

$\int\limits^5_1 {x/(2+x^{3}) } \, dx$ =f(x)= $x/2+x^{3}$

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)= $[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}$

$\lim_{n \to \infty}$ ∑f(a+iΔx)Δx=

$\lim_{n \to \infty}$ ∑ $n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n$

=4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$

Hence the expression of integral as a limit of Riemann sums of given integral $\int\limits^5_b {1} \, x/(2+x^{3}) dx$ is 4 $\lim_{n \to \infty}$ ∑ $n(n+4i)/2n^{3}+(n+4i)^{3}$ from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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ratelena [41]

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