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garik1379 [7]
3 years ago
12

-12(-j)(-3k) what’s the answer

Mathematics
1 answer:
trapecia [35]3 years ago
4 0

The answer is: -36jk

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I just need to know how to do these questions in the picture above^?
Sav [38]
In the second one I'm pretty sure you just measure the length of the points.
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3 years ago
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Please can someone help?
alexandr402 [8]

Hey there! :)

Answer:

(5, -2), or x = 5 and y = -2.

Step-by-step explanation:

We can solve the two equations algebraically by eliminating a variable:

2x + 5y = 0

3x - 4y = 23

Eliminate the x variable by finding the least common multiple and multiplying both equations:

3(2x + 5y = 0)

2(3x - 4y = 23)

Distribute and subtract the bottom equation from the top:

6x + 15y = 0

6x - 8y = 46

------------------

0x + 23y = -46

23y = -46

y = -2.

Plug in y into an equation to solve for x:

2x + 5(-2) = 0

2x - 10 = 0

2x = 10

x = 5. Therefore:

The solution to this equation is (5, -2), or x = 5 and y = -2.

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3 years ago
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Given g(x) = (x - 3)2 and h(x) = 2x + 1, which of the following is (g.h)(5)?
Vadim26 [7]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
At a carnival, single rides cost $2 each, and all day ride passes cost $15. The total revenue for the day was $2,960.
makkiz [27]

Answer:

2x+15y=2960

Step-by-step explanation:

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3 years ago
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If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

\displaystyle \int_a^b f(x) \, dx = b f(b) - a f(a) - \int_{f(a)}^{f(b)} f^{-1}(x) \, dx

Let f(x) = \sqrt{1 + x^3}. Compute the inverse:

f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}

and we immediately notice that f^{-1}(x+1)=\sqrt[3]{x^2+2x}.

So, we can write the given integral as

\displaystyle \int_0^2 f^{-1}(x+1) + f(x) \, dx

Splitting up terms and replacing x \to x-1 in the first integral, we get

\displaystyle \int_1^3 f^{-1}(x) \, dx + \int_0^2 f(x) \, dx = 2 f(2) - 0 f(0) = 2\times3+0\times1=\boxed{6}

7 0
1 year ago
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