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OleMash [197]
3 years ago
7

D. 2x2+3x-x2+y+y-(x2+2y)=3

Mathematics
1 answer:
STatiana [176]3 years ago
4 0

Answer:

x=1

Step-by-step explanation:

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How do I do this?<br>*Look at the directions in the photo*​
lora16 [44]

Answer:

Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2

Step-by-step explanation:

We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\

As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2

For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2

For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2

Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2

7 0
3 years ago
Draw a rectangle that has an area of 8 units square and a perimeter of 12 units. What are the side lengths
choli [55]

Answer:

4 by 2

Step-by-step explanation:

you can basically guess and check with this question but I knew if it was a rectangle then 2 sides would be larger than the other. So I started off figuring out what times what equals 8 and I got 2 and 4. So I put those in for the side lengths and I got 12.

8 0
3 years ago
How to simplify 3-3(x-2)
umka2103 [35]
Well u subtract -3then multiply so it's 3-3 (×-2) equals -3
8 0
3 years ago
-5 1/2 as an improper fraction
Rudik [331]
-11/2
Multiply 5 and 2, then add 1
-11/2, Hope this helps!
6 0
3 years ago
Evaluate the following expression:<br>7× + 5y​
irina [24]

Answer:

I think this question is incomplete or maybe incorrect but if it's OK then the answer would be 7x + 5y.

Step-by-step explanation:

the answer remains the same because the question has no like terms so no further calculations can be made.

5 0
3 years ago
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