Answer:
![V(X) = E(X^2)-[E(X)]^2=349.2-(18.6)^2=3.24](https://tex.z-dn.net/?f=V%28X%29%20%3D%20E%28X%5E2%29-%5BE%28X%29%5D%5E2%3D349.2-%2818.6%29%5E2%3D3.24)
The expected price paid by the next customer to buy a freezer is $466
Step-by-step explanation:
From the information given we know the probability mass function (pmf) of random variable X.
<em>Point a:</em>
- The Expected value or the mean value of X with set of possible values D, denoted by <em>E(X)</em> or <em>μ </em>is
Therefore
- If the random variable X has a set of possible values D and a probability mass function, then the expected value of any function h(X), denoted by <em>E[h(X)]</em> is computed by
![E[h(X)] = $\sum_{D} h(x)\cdot p(x)](https://tex.z-dn.net/?f=E%5Bh%28X%29%5D%20%3D%20%24%5Csum_%7BD%7D%20h%28x%29%5Ccdot%20p%28x%29)
So 
and
![E[h(X)] = $\sum_{D} h(x)\cdot p(x)\\E[X^2]=$\sum_{D}x^2\cdot p(x)\\ E(X^2)=16^2\cdot 0.3+18^2\cdot 0.1+20^2\cdot 0.6\\E(X^2)=349.2](https://tex.z-dn.net/?f=E%5Bh%28X%29%5D%20%3D%20%24%5Csum_%7BD%7D%20h%28x%29%5Ccdot%20p%28x%29%5C%5CE%5BX%5E2%5D%3D%24%5Csum_%7BD%7Dx%5E2%5Ccdot%20p%28x%29%5C%5C%20E%28X%5E2%29%3D16%5E2%5Ccdot%200.3%2B18%5E2%5Ccdot%200.1%2B20%5E2%5Ccdot%200.6%5C%5CE%28X%5E2%29%3D349.2)
- The variance of X, denoted by V(X), is
![V(X) = $\sum_{D}E[(X-\mu)^2]=E(X^2)-[E(X)]^2](https://tex.z-dn.net/?f=V%28X%29%20%3D%20%24%5Csum_%7BD%7DE%5B%28X-%5Cmu%29%5E2%5D%3DE%28X%5E2%29-%5BE%28X%29%5D%5E2)
Therefore
![V(X) = E(X^2)-[E(X)]^2\\V(X)=349.2-(18.6)^2\\V(X)=3.24](https://tex.z-dn.net/?f=V%28X%29%20%3D%20E%28X%5E2%29-%5BE%28X%29%5D%5E2%5C%5CV%28X%29%3D349.2-%2818.6%29%5E2%5C%5CV%28X%29%3D3.24)
<em>Point b:</em>
We know that the price of a freezer having capacity X is 60X − 650, to find the expected price paid by the next customer to buy a freezer you need to:
From the rules of expected value this proposition is true:
We have a = 60, b = -650, and <em>E(X)</em> = 18.6. Therefore
The expected price paid by the next customer is
Answer:
The number is 7.
Step-by-step explanation:
4n - 7 = 21 Add 7 on both sides
4n = 28 Isolate the variable by dividing 4 on both sides
n= 7
<h3><u><em>
Hope this helps!!!
</em></u></h3><h3><u><em>
Please mark this as brainliest!!!
</em></u></h3><h3><u><em>
Thank You!!!
</em></u></h3><h3><u><em>
:)</em></u></h3>
To calculate the IQR, we need the radian, which is the middle number of each column, namely (86,82) for each exam.
Above the middle number, we have 5 values. The middle value (of the upper part) is Q3, which is on the third line, or (92,85).
Below the middle number, we also have 5 values. The middle (of the lower half) is Q1, which is on the 9th line (80,78)
The IQR is the difference between Q3 and Q1, namely
(92-80, 85-78) = (12, 7)
Since 12>7, we conclude that the IQR of the mid-term is higher than the final.
The answer is 0.2777777777 (repeating)
Or 0.28 (Rounded)
I hope this helps you!
Answer:
320
Step-by-step explanation:
Using the rules of exponents
• 
⇔ 
• 
× ⇔ 
simplifying 
= 4³ × x³ = 64x³
(5x³) ×
= 5x³ × 64x³ = (5 × 64) × (x³ × x³) = 320
= 320
