This is in the form mx + b
so,
g(x) = -3x - 5 + 9
-3x + 4
the b is the y-int
y-int = 4
The probability of winning exactly 21 times is 0.14 when the probability of winning the arcade game is 0.659.
We know that binomial probability is given by:
Probability (P) = ⁿCₓ (probability of 1st)ˣ x (1 - probability of 1st)ⁿ⁻ˣ
We are given that:
Probability of winning on an arcade game = P(A) = 0.659
So, the Probability of loosing on an arcade game will be = P'(A) = 1 - 0.659 = 0.341
Number of times the game is being played = 30
We have to find the Probability of winning exactly 21 times.
Here,
n = 30
x = 21
P(A) = 0.659
P'(A) = 0.341
Using the binomial probability formula, we get that:
Probability of winning exactly 21 times :
P(21 times) = ³⁰C₂₁ (0.659)²¹ x (0.341)⁷
P( 21 times ) = 0.14
Therefore, the probability of winning exactly 21 times is 0.14
Learn more about " Binomial Probability " here: brainly.com/question/12474772
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Whats your question? What are you trying to find?
Step-by-step explanation:
i think it means that when negative tow crosses the equal sign, as in a calculation,it becomes positive
eg. -2 +z=0
z =2
You will receive a free beverage and free desert on your 60th visit.
Beverage- 1, 2, 3, 4, 5, 6
Visits- 12, 24, 36 ,48 ,60
Desert- 1, 2, 3 ,4
Visits- 15, 30, 45, 60
Notice how for beverages at 60 visits you get your 6th drink for free, and for deserts, at you 60 visits you receive your 4 free desert.
So, since both numbers have the same number (60) of visits which is their common multiple between the 2, you answer is 60.
