If a sphere's surface area is doubled, what is the corresponding change in radius?

2 answers:

6 0

The radius is increased by \sqrt(2) times, so b must be the missing choice that we're looking for. The formula for sphere's surface area is 4*pi*r^2. When r is increased to be \sqrt(2)*r, the new surface area becomes 4*pi*(2*r^2)=8*pi*(r^2), doubling the original surface area.

Sonbull [250]3 years ago

5 0

The radius is increased by sqrt2 times

It must be b

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