Answer:
y = 6cos(π/2)t
Step-by-step explanation:
Given in the question that,
in a simple harmonic motion in which
at t=0 the amplitude is 6 cm, so the simple harmonic motion will be in cosine form. As in case of sine function, the value of function at t=0 is 0.
And,
the period is given as 4 sec
We know that model equation of simple harmonic motion is
<h3>y = a. cosb(t + c) + d</h3>
here,
a is amplitude
c is Horizontal shift or phase shift
d is Vertical shift
<h3>Step1</h3><h3>Find b</h3>
Period = 2 π / b
4 = 2π / b
b = 2π/4
b = 1π/2
<h3>Step2</h3><h3>Find shifts</h3>
Horizontal and vertical shifts are 0.
So, c = 0 and d = 0
<h3>Step3</h3><h3>Plug those values in the above in the equation</h3>
y = 6cos π/2 (t + 0) + 0
y = 6cos(π/2)t
G(x) = 3x + 5
y = 3x + 5
3x = y - 5
x = (y - 5)/3
Therefore, g^-1(x) = (x - 5)/3
1
Explanation
It’s correct
Answer:
8.9cm
Step-by-step explanation:
Volume of a cube = L × L × L = L³
710 = L³
L = ³√710
L= 8.9 cm
The foot length of Sandy is 10.5 inches
<u>Solution:</u>
<em>Assume nose and foot length are proportional</em>
Therefore,
Let "n" be the nose length and "f" be the foot length
Then,
n = kf ------ eqn 1
Where "k" is the constant of proportionality
<em><u>Cindy's nose is 1.9 inches long and her foot is 9.5 inches long</u></em>
n = 1.9 inches'
f = 9.5 inches
Substitute these in eqn 1
Thus k = 0.2
<em><u>Sandy's nose is 2.1 inches long, we have to find the foot length</u></em>
n = 2.1
k = 0.2
f = ?
Substitute these in eqn 1
Thus foot length of Sandy is 10.5 inches
