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Over [174]
3 years ago
12

What is 0.015 x 1.5=

Mathematics
1 answer:
alukav5142 [94]3 years ago
7 0
The answer is 0.0225
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Find the distance between the two points rounding to the nearest tenth if necessary (-1,4) and (4,-8)
laila [671]

Answer:

13 units

Step-by-step explanation:

\sqrt{(4--1)^{2}+(-8-4)^{2}  }

=\sqrt{5^{2}+(-12)^{2} }

=\sqrt{25 + 144}

=\sqrt{169}

=13 units

5 0
3 years ago
Please help asap ty just for numbers 29 31 and 32
Allisa [31]

Answer:

105, D, 13,9899/138530? not sure on that one

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3 years ago
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Find the degree of the polynomial<br> 2x^4y^2+9x^2y^5-3x^4y^4
coldgirl [10]

Answer:

the polynomial has degree 8

Step-by-step explanation:

Recall that the degree of a polynomial is given by the degree of its leading term (the term with largest degree). Recall as well that the degree of a term is the maximum number of variables that appear in it.

So, let's examine each of the terms in the given polynomial, and count the number of variables they contain to find their individual degrees. then pick the one with maximum degree, and that its degree would give the actual degree of the entire polynomial.

1) term  2\,x^4\,y^2  contains four variables "x" and two variables "y", so a total of six. Then its degree is: 6

2) term  9\,x^2\,y^5  contains two variables "x" and five variables "y", so a total of seven. Then its degree is: 7

3) term  -3\,x^4\,y^4  contains four variables "x" and four variables "y", so a total of eight. Then its degree is: 8

This last term is therefore the leading term of the polynomial (the term with largest degree) and the one that gives the degree to the entire polynomial.

8 0
3 years ago
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The swimming pool at spring valley high is a rectangle with a width of 65 meters and a length of 30 meters. Around the perimeter
pentagon [3]

65+w*30+w i think is the answer


4 0
3 years ago
Can someone answer these questions ? thank you
Naya [18.7K]

Answer:

Step-by-step explanation:

12a)To rationalize the denominator, multiply the denominator and numerator by √5.

\frac{15}{\sqrt{5}}=\frac{15*\sqrt{5}}{\sqrt{5}*\sqrt{5}}\\\\=\frac{15\sqrt{5}}{5}\\\\=3\sqrt{5}

b) (a+b)² = a² + 2ab + b²

(1 +√3)² = 1² + 2*1*√3 + (√3)²

= 1 + 2√3 + 3

= 4 + 2√3

a = 4 ; b =2

13) (a + b)(a - b) = a² - b²

\frac{(6-\sqrt{5})(6+\sqrt{5})}{\sqrt{31}}=\frac{6^{2}-(\sqrt{5})^{2}}{\sqrt{31}}\\\\ =\frac{36-5}{\sqrt{31}}\\\\=\frac{31}{\sqrt{31}}\\\\=\frac{31*\sqrt{31}}{\sqrt{31}*\sqrt{31}}\\\\=\frac{31\sqrt{31}}{31}\\\\=\sqrt{31}

5 0
3 years ago
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