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Tom [10]
3 years ago
9

If you spin the spinner below two times, are the events independent or dependent?

Mathematics
1 answer:
tatuchka [14]3 years ago
8 0

Answer:

A: Independent

Step-by-step explanation:

You might be interested in
Two thirds of a number decreased by six is two. what is the number?
Kisachek [45]
Answer:  The number is:  " 12 ". 

____________________________________
  Let "x" represent "the unknown number" (for which we wish to solve.

The expression:

\frac{2}{3} x  <span>− 6  =  2  ;   Solve for "x" ;  
</span>_______________________________________________
Method 1) 

   Add "6" to EACH SIDE of the equation;
_______________________________________________
       →   \frac{2}{3} x  − 6  + 6 =  2 + 6 ;

to get:

      →   \frac{2}{3} x = 8 ;
______________________________________________
Multiply each side of the equation by "\frac{3}{2}" ; to isolate "x" on one side of the equation ; and to solve for "x" ;
______________________________________________
     → \frac{3}{2} * \frac{2}{3} x = 8 * \frac{3}{2} ;

       →  x = 8 * \frac{3}{2} ;

                = \frac{8}{1} * \frac{3}{2} ;

                = \frac{8*3}{1*2} ;
       
                = \frac{24}{2} ;
 
                = <span>1<span>2 .</span></span>
______________________________________________
  x =  12 .
______________________________________________
Method 2)
______________________________________________
\frac{2}{3} x  − 6  =  2  ;   Solve for "x" ; 

   Add "6" to EACH SIDE of the equation;
_______________________________________________
       →   \frac{2}{3} x  − 6  + 6 =  2 + 6 ;

to get:
      →   \frac{2}{3} x = 8 ;
______________________________________________
Multiply each side of the equation by "3" ; to get rid of the "fraction" ;
               → 3 * \frac{2}{3} x = 8 * 3  ;
               → \frac{3}{1} * \frac{2}{3} x = 8 * 3 ;
               → \frac{3*2}{1*3}  x = 8 * 3 
               → \frac{6}{3} x = 24 ; 

                → 2x = 24 ;

 →  Divide each side of the equation by "2" ; to isolate "x" on one side of the equation; & to solve for "x" : 
 
                    2x / 2 = 24 / 2  ;

                        x = 12 .
__________________________________________________
Method 3).
__________________________________________________
\frac{2}{3} x  − 6  =  2  ;   Solve for "x" ;  
_______________________________________________
Add "6" to EACH SIDE of the equation;
_______________________________________________
       →   \frac{2}{3} x  − 6  + 6 =  2 + 6 ;

to get:

      →   \frac{2}{3} x = 8 ;
______________________________________________
Now, divide each side of the equation by " \frac{2}{3} " ;
  to isolate "x" on one side of the equation; & to solve for "x" ;
___________________________________________________
{\frac{2}{3} x }  /  {\frac{2}{3}}  =  8 / {\frac{2}{3}} ;

to get:  x =  8 / {\frac{2}{3}} ;

                =  8 * (\frac{3}{2} ;

                =  \frac{8}{1}  *  \frac{3}{2} ;

                =  \frac{8*3}{1*2} ;

                =  \frac{24}{2} ;

                = 12 ; 
___________________________________________
                         x = 12 .
___________________________________________
NOTE:  Variant:  (in "Methods 2 & 3") :
___________________________________________
At the point where:
___________________________________________
 =  8 * (\frac{3}{2}) ;

  =  \frac{8}{1}  *  \frac{3}{2} ;
__________________________________________
  We can cancel out the "2" to a "1" ; and we can cancel out the "8" to a "4" ;
__________________________________________
  {since: "8÷2 = 4" ; and since:  "2÷2 =1" } ;
__________________________________________
and we can rewrite the expression:
__________________________________________
 \frac{8}{1}  *  \frac{3}{2} ;
__________________________________________
as:   \frac{4}{1}  *  \frac{3}{1} ; 
__________________________________________
which equals:
__________________________________________
→  \frac{4*3}{1*1} ; 

   =   \frac{12}{1} ;

            =  12 .
__________________________________________
         x = 12 . 
__________________________________________
Answer:  The number is:  " 12 ". 
__________________________________________
8 0
4 years ago
Please please answer
Nostrana [21]

Answer:

thanks for your support of the personal information on the direction of economics class

3 0
2 years ago
What is the simplified form of (3x + 2)(4x – 3)? Use a table.
ch4aika [34]

Answer:

Step-by-step explanation:

6 0
3 years ago
About cost 92,000 and depreciates in value by 15% per year how much will the boat be worth after 10 years
Lorico [155]
292.296296296296296
I don't know if this is right or not but at least I attempted to help out. 
And I'm very sorry if this answer is wrong.
5 0
3 years ago
You have two circular flower beds, as shown. The sum of the areas of two flower beds is 136 pi square feet. Find the radius of e
finlep [7]

Answer:

Radius of larger flower bed = 10 feet

Radius of smaller flower bed = 6 feet

Step-by-step explanation:

<u>Complete question:</u>

"You have two circular flower beds, as shown. The sum of the areas of two flower beds is 136 pi square feet. Find the radius of each bed.<em>"</em>

<em>Radius of larger flower bed = r</em>

<em>Radius of smaller flower bed = r - 4</em>

<em />

Now,

Area of circle is  \pi r^2

Since, total area is 136\pi, we can write:

\pi r^2 + \pi (r-4)^2=136\pi

Expanding and solving for r:

\pi r^2 + \pi (r-4)^2=136\pi\\r^2+(r-4)^2=136\\r^2 + r^2 - 8r + 16 = 136\\2r^2-8r-120=0\\2(r+6)(r-10)=0\\r=-6,10

Radius cannot be negative, so r = 10  &  r-4 = 10 -4 = 6

Radius of larger flower bed = 10 feet

Radius of smaller flower bed = 6 feet

8 0
3 years ago
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