Question

Show that f(x)=(x-2)^3+8 is one to one algebraically

Answer 1

What im thinking is this: F(a) = f(b) so have 2 equations written and plug a into one and b in the other

(a-2)^3+8   = a^3-8+8 = a^3

                                             =            a^3 = b^3 square root both side = a=b
 (b-2)^3+8  = b^3-8+8 = b^3


Thus it is 1:1.