4 years ago

Show that f(x)=(x-2)^3+8 is one to one algebraically

1 answer:

3 0

What im thinking is this: F(a) = f(b) so have 2 equations written and plug a into one and b in the other

(a-2)^3+8 = a^3-8+8 = a^3

= a^3 = b^3 square root both side = a=b
<span>(b-2)^3+8 = b^3-8+8 = b^3

Thus it is 1:1.</span>

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