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suter [353]
3 years ago
15

Show that f(x)=(x-2)^3+8 is one to one algebraically

Mathematics
1 answer:
Lelu [443]3 years ago
3 0
What im thinking is this: F(a) = f(b) so have 2 equations written and plug a into one and b in the other

(a-2)^3+8   = a^3-8+8 = a^3

                                             =            a^3 = b^3 square root both side = a=b
 <span>(b-2)^3+8  = b^3-8+8 = b^3


Thus it is 1:1.</span>
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