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4 years ago

5

Aimee is flying a plane for the first time! The air traffic controller tells her to fly at 500m above the ground or higher. Writ

e an inequality that is true only for elevations (h) at which Aimee should fly.

1 answer:

Gelneren [198K]4 years ago

6 0

She needs to fly at 500 or higher which means that the equation needs to include
$\geqslant$

The answer is
$h \geqslant 500$

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4 years ago

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3 years ago

Read 2 more answers

Beginning with the equation 2x + 8y = 12, write an additional equation that would create:

kramer

Answer:

[see below]

Step-by-step explanation:

A system of equations with no solution would show parallel lines. We just have make a equation that is parallel to the original equation.

The slope of 2x + 8y = 12 is $-\frac{1}{4}$ , and it's y-intercept is $\frac{3}{2}$ .

Since parallel lines have the same slope but not the same y-intercept, I would use $y=-\frac{1}{4}x+3$ .

Any equation that has -1/4 as the slope would work.

When graphed together, they show as a system with no solution.

Hope this helps.

3 0

3 years ago

A parallelogram has sides of length 30 centimeters and 18 centimeters. One of its angles measure 58 degrees. Which is the best e

Elanso [62]

Answer:

D

Step-by-step explanation:

I'm assuming you're looking for area here.

The formula is b * h = A

So all you're doing is multiplying 30 by 18 to get 540.

3 0

3 years ago

Hallmark would like to test the hypothesis that those celebrating Valentine's Day will spend more than an average of $125 on gif

Vaselesa [24]

Answer:

We conclude that those celebrating Valentine's Day spend more than an average of $125 on gifts.

Step-by-step explanation:

We are given that Hallmark would like to test the hypothesis that those celebrating Valentine's Day will spend more than an average of $125 on gifts.

A random sample of 18 people celebrating Valentine's Day spent an average of $148.50 with a standard deviation of $34.90.

<u><em>Let </em></u> $\mu$ <u><em> = average amount spent on gifts celebrating Valentine's Day</em></u>

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ $125 {means that those celebrating Valentine's Day spend less than or equal to an average of $125 on gifts}

Alternate Hypothesis, $H_A$ : $\mu$ > $125 {means that those celebrating Valentine's Day spend more than an average of $125 on gifts}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average amount spent = $148.50

s = sample standard deviation = $34.90

n = sample of people = 18

So, <u>test statistics</u> = $\frac{148.50-125}{\frac{34.90}{\sqrt{18} } }$ ~ $t_1_7$

= 2.857

The value of the sample test statistics is 2.857.

<u>Now, P-value of the test statistics is given by the following formula;</u>

P-value = P( $t_1_7$ > 2.857) = <u>0.0056</u>

Because in the t table the critical value of 2.857 at 17 degree of freedom will lie between P = 1% and P = 0.5%.

Now, since P-value of test statistics is less than the level of significance as 0.01 > 0.0056, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that those celebrating Valentine's Day spend more than an average of $125 on gifts.

3 0

3 years ago