All categories

3 years ago

Find the slope of the line through (0,5) and (5,5)

Mathematics

2 answers:

Fofino [41]3 years ago

6 0

Answer:

Step-by-step explanation:

zvonat [6]3 years ago

4 0

Answer: 0

Step-by-step explanation:

The slope can be found by using the formula:

m= y 2-y 1 / x 2-x 1

where m is the slope and x 1 y 1 and x 2 y 2 are the two points in the line

Substituting the values from the points in the problem gives:

m= 5-5/5-0

m=0/5

the slope of the line is zero.

You might be interested in

When x = a is a zero of a polynomial function f, the three statements below are true.

Lunna [17]

Answer:

x = a is a zero of a polinomial f(x), this is the same than: f(x) has a root at x = a

Then: f(a) = 0.

a) x = a is a ____ of the polynomial equation f(x) = 0.

If we define f(x) = 0, then x = a is a solution of the equation.

Then the complete sentence is:

x = a is a solution of the polynomial equation f(x) = 0.

b) ____ is a factor of the polynomial f(x).

Remember that if a polynomial p(x) of degree n has the roots x₁, x₂, ..., xₙ

Then we can write p(x) in the factorized form as:

p(x) = A*(x - x₁)*(x - x₂)*...*(x - xₙ)

Where A is a real number.

Then if in this case we know that a is a root of f(x), then (x - a) is a factor of the polynomial f(x), then the complete sentence is:

(x - a) is a factor of the polynomial f(x).

c) (a, 0) is a ____ of the graph f(x)

We usually use the notation y = f(x).

Then the points of the form (x, f(x)) are the points that belong to the graph of f(x).

In this case, the point (a, f(a)) = (a, 0)

This point belongs to the graph of f(x), then the complete sentence can be written as:

(a, 0) is a point of the graph f(x).

4 0

2 years ago

In the expression 2003-02-02-00-00_files/i0020000, the number 4 is called the __________.

elixir [45]

Base is the correct answer

5 0

3 years ago

Help me me me me plz thx if you do

prohojiy [21]

Answer:

75% left is not taken up so do the Ab to the other

Step-by-step explanation:

0.75 sorry if Im wrong

6 0

3 years ago

Write a rational function that matches the given statement:

djyliett [7]

Answer:

i put a graph in there

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csf%20%5Clim_%7Bx%20%5Cto%20%5Cinfty%7D%20%5Ccfrac%7B%5Csqrt%7Bx-1%7D-2x%20%7D%7Bx-7%7D" id=

BARSIC [14]

<h3>Answer: -2</h3>

======================================================

Work Shown:

$\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}\left(\sqrt{x-1}-2x\right) }{ \frac{1}{x}\left(x-7\right) }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \frac{1}{x}*\sqrt{x-1}-\frac{1}{x}*2x }{ \frac{1}{x}*x-\frac{1}{x}*7 }\\\\\\$

$\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}}*\sqrt{x-1}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x^2}*(x-1)}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{\frac{1}{x}-\frac{1}{x^2}}-2 }{ 1-\frac{7}{x} }\\\\\\\displaystyle L = \frac{ \sqrt{0-0}-2 }{ 1-0 }\\\\\\\displaystyle L = \frac{-2}{1}\\\\\\\displaystyle L = -2\\\\\\$

-------------------

Explanation:

In the second step, I multiplied top and bottom by 1/x. This divides every term by x. Doing this leaves us with various inner fractions that have the variable in the denominator. Those inner fractions approach 0 as x approaches infinity.

I'm using the rule that

$\displaystyle \lim_{x\to\infty} \frac{1}{x^k} = 0\\\\\\$

where k is some positive real number constant.

Using that rule will simplify the expression greatly to leave us with -2/1 or simply -2 as the answer.

In a sense, the leading terms of the numerator and denominator are -2x and x respectively. They are the largest terms for each, so to speak. As x gets larger, the influence that -2x and x have will greatly diminish the influence of the other terms.

This effectively means,

$\displaystyle L = \lim_{x\to\infty} \frac{ \sqrt{x-1}-2x }{ x-7 } = \lim_{x\to\infty} \frac{ -2x }{ x} = -2\\\\\\$

I recommend making a table of values to see what's going on. Or you can graph the given function to see that it slowly approaches y = -2. Keep in mind that it won't actually reach y = -2 itself.

5 0

3 years ago