Hello!
Let 'a' stand for adult tickets and 'c' for children tickets.
a + c = 15
(Both adult and children tickets make up a total of 15 tickets).
30a + 20c = 330
a = 3
c = 12
A N S W E R:
William bought 3 adults tickets and 12 children's tickets.
It would be 2(x+3)(x+1)=0
Explanation:
I used factor by grouping. You multiply the first term (2) by the last term (6). This gives you 12 then take the factors of 12 that add up to the middle term 8. You get 6 and 2.
It should look like 2x^2+6x+2x+6=0
when you do factor by grouping you factor the first two terms and then the last two terms separately. So you get (2x+2) and (x+3). (2x+2) could be factored into 2(x+1). Then you put everything together and get 2(x+3)(x+1)=0
Answer:
b. (2, 5, 3)
Step-by-step explanation:
Trying the offered choices seems the fastest way to find the answer. The second choice works in all equations, hence is the solution.
Another strategy you can use is to see if the equations are dependent. Here, it looks like adding twice the third equation to the other two eliminates at least the x- and y-variables. If that eliminates z, then there are infinite solutions. Instead, it gives the equation ...
7z = 21
z = 3 . . . . . divide by 7
This answer is consistent with choice B, confirming that answer and eliminating the other choices.
Answer:
ok so the answer is 1/32 or 0.03125
Step-by-step explanation:
Hope this helped!!
