Answer:
2.4×10^6
Step-by-step explanation:
Put the numbers where the variables are and do the arithmetic. You can enter the numbers in scientific notation into your (scientific) calculator and have it show you the result in the same format.
r = (3.8×10^5)^2/(5.9×10^4) . . . . . denominator parentheses are required
Please note that in the above expression, parentheses are required around the denominator number. This is because it is a product of two numbers. In your pocket calculator or spreadsheet, you can enter that value as a single number (not a product). Parentheses are not required when you can do that.
r = (3.8²/5.9)×10^(5·2-4) ≈ 2.4×10^6
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The "exact" value is a repeating decimal with a long repeat. We have rounded to 2 significant digits here because the input numbers have that number of significant digits.
Answer:
b) When will the number of deer be 600?
Step-by-step explanation:
Answer:
50,,
Step-by-step explanation:
so you take 80percent of 250,, and deduct from medical expenses which becomes 50
Answer:
Slower.
Step-by-step explanation:
I belive it is slower because the scooter was 30 feet per 2 seconds. 30+30+60 feet, 2+2= 4 seconds= 60 feet and 4 seconds which makes the 55 feet per 4 seconds slower.
The answer to this question would be: 85/99
In this question, Suzan is taking 8 marble from a bag containing 4 red marbles, 4 green ones, 2 white ones, and 2 purple ones. The total marble in the bag should be: 4+4+2+2= 12. The question is how much the probability to get <4 red marble. In this question, the green, white and purple is not specified so you can join them into not red group. It will be easier to find the probability of "have all the red one" which mean Suzan take 4 red marble and 4 not-red marble<span>
Ways to take 8 marble out of 12=12C5= 12!/4!8!= </span>495
Ways to take 4 red marble out of 4= 4C4= 1
Ways to take 4 not red marble out of 8= 8C4= 8!/4!4!= 70
Probability to <span>have all the red ones= 1*70/495= 14/99
</span>Then the probability does not have all the red ones= 99/99 - 14/99= 85/99
