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3 years ago

In the equation Y = 8x+ 5 the name for y are

Mathematics

1 answer:

VLD [36.1K]3 years ago

4 0

Answer:

The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

Step-by-step explanation:

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Anyways.....Im failing math :D

melomori [17]

Answer:

SELENA IS THE BEST SINGER IN THE WORLD OTHER THAN NICKI MINAJA

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m

Elenna [48]

Answer:

Part a: The probability of no arrivals in a one-minute period is 0.000045.

Part b: The probability of three or fewer passengers arrive in a one-minute period is 0.0103.

Part c: The probability of no arrivals in a 15-second is 0.0821.

Part d: The probability of at least one arrival in a 15-second period is 0.9179.

Step-by-step explanation:

Airline passengers are arriving at an airport independently. The mean arrival rate is 10 passengers per minute. Consider the random variable X to represent the number of passengers arriving per minute. The random variable X follows a Poisson distribution. That is,

$X \sim {\rm{Poisson}}\left( {\lambda = 10} \right)$

The probability mass function of X can be written as,

$P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}};x = 0,1,2, \ldots$

Substitute the value of λ=10 in the formula as,

$P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{{\left( {10} \right)}^x}}}{{x!}}$

Part a:

The probability that there are no arrivals in one minute is calculated by substituting x = 0 in the formula as,

$\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ - 10}}{{\left( {10} \right)}^0}}}{{0!}}\\\\ = {e^{ - 10}}\\\\ = 0.000045\\\end{array}$

The probability of no arrivals in a one-minute period is 0.000045.

Part b:

The probability mass function of X can be written as,

$P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}};x = 0,1,2, \ldots$

The probability of the arrival of three or fewer passengers in one minute is calculated by substituting \lambda = 10λ=10 and x = 0,1,2,3x=0,1,2,3 in the formula as,

$\begin{array}{c}\\P\left( {X \le 3} \right) = \sum\limits_{x = 0}^3 {\frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}}} \\\\ = \frac{{{e^{ - 10}}{{\left( {10} \right)}^0}}}{{0!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^1}}}{{1!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^2}}}{{2!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^3}}}{{3!}}\\\\ = 0.000045 + 0.00045 + 0.00227 + 0.00756\\\\ = 0.0103\\\end{array}$

The probability of three or fewer passengers arrive in a one-minute period is 0.0103.

Part c:

Consider the random variable Y to denote the passengers arriving in 15 seconds. This means that the random variable Y can be defined as $\frac{X}{4}$

$\begin{array}{c}\\E\left( Y \right) = E\left( {\frac{X}{4}} \right)\\\\ = \frac{1}{4} \times 10\\\\ = 2.5\\\end{array}$

That is,

$Y\sim {\rm{Poisson}}\left( {\lambda = 2.5} \right)$

So, the probability mass function of Y is,

$P\left( {Y = y} \right) = \frac{{{e^{ - \lambda }}{\lambda ^y}}}{{y!}};x = 0,1,2, \ldots$

The probability that there are no arrivals in the 15-second period can be calculated by substituting the value of (λ=2.5) and y as 0 as:

$\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ - 2.5}} \times {{2.5}^0}}}{{0!}}\\\\ = {e^{ - 2.5}}\\\\ = 0.0821\\\end{array}$

The probability of no arrivals in a 15-second is 0.0821.

Part d:

The probability that there is at least one arrival in a 15-second period is calculated as,

$\begin{array}{c}\\P\left( {X \ge 1} \right) = 1 - P\left( {X < 1} \right)\\\\ = 1 - P\left( {X = 0} \right)\\\\ = 1 - \frac{{{e^{ - 2.5}} \times {{2.5}^0}}}{{0!}}\\\\ = 1 - {e^{ - 2.5}}\\\end{array}$

$\begin{array}{c}\\ = 1 - 0.082\\\\ = 0.9179\\\end{array}$

The probability of at least one arrival in a 15-second period is 0.9179.

7 0

3 years ago

G−9=−19 What does g=???

Free_Kalibri [48]

Answer:

g=-19+9

g=-10

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Which of the following options have the same value as

Keith_Richards [23]

Question:

Which of the following options have the same value as 65% of 20?

Choose 2 answers:

(A) 0.65⋅20

(B) 65/100 divided by 20

(D) 65 * 20

Answer:

Option A has the same value as 65% of 20

Step-by-step explanation:

Let x be the value of 65% of 20

$x = 65\% of 20$

$x = \frac{65}{100} \times 20$

$x =0.65 \times 20$

$x =13$

Thus 65% of 20 is 13

Now ,

Solving Option A

=> $(0.65) \cdot (20)$

=> 13

Solving Option B

=> 65/100 divided by 20

=> $\frac{\frac{65}{100}}{20}$

=> $\frac{0.65}{20}$

=>0.0325

Solving Option C

=>65/20 * 100

=> $\frac{65}{20} \times 100$

=> $3.25 \times 100$

=>325

Solving Option D

=> 65 * 20

=> $65 \times 20$

=> 1300

8 0

3 years ago

Read 2 more answers

Please help worth 20 points will mark brainliest

ddd [48]

Answer:

P(t)= 100t + 150

Step-by-step explanation:

If the price for 6 hours of studio time is 600 dollars, that means every hour the studio is used it costs 100 dollars. Since the fixed fee is 150 dollars, that is added to the cost of how many hours the studio is used.

I hope this helped you. If it did Brainilest is appreciated.

3 0

3 years ago

In the equation Y = 8x+ 5 the name for y are​

In the equation Y = 8x+ 5 the name for y are