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2 years ago

Need help with this math, learnt this today still very confused.

Mathematics

1 answer:

seraphim [82]2 years ago

6 0

The answer for 4 is 17.5 I’m pretty sure

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Ms. Wilson studied her biology students' homework and test scores. She found that students who completed more homework did not

Nataly [62]

Answer:

The Answer is the Number 2,

I mean Point #2!

I Hope this WORKS! 100%

3 0

2 years ago

If tan theta = 10/13 and cos theta > 0 then sin2theta is what ?

svetoff [14.1K]

$sin2\alpha = \frac{260}{269}$

Step-by-step explanation:

We have , $Tan\alpha = \frac{Perpendicular}{Base} = \frac{10}{13}$ ,

We know that $sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }$

Substituting values of P & B , $sin\alpha = \frac{10}{\sqrt{10^{2} + 13^{2}} } = \frac{10}{\sqrt{269} }$

Now , $sin2\alpha = 2sin\alpha cos\alpha = 2sin\alpha \sqrt{1 - (sin\alpha)^{2} }$

⇒ $sin2\alpha =$ $\frac{10}{\sqrt{269} }$ × $\sqrt{1 - (\frac{10}{\sqrt{269} })^{2} }$ ×2

⇒ $sin2\alpha = \frac{20}{\sqrt{269} }( \sqrt{\frac{269 - 100}{269} } )$

⇒ $sin2\alpha = \frac{20}{\sqrt{269} }( \sqrt{\frac{169 }{269} } )$

⇒ $sin2\alpha = \frac{260}{\sqrt{269} }( \sqrt{\frac{1}{269} } )$

⇒ $sin2\alpha = \frac{260}{269}$

6 0

3 years ago

The diameter of a circle is 5 ft. Find the circumference TO THE NEAREST TENTH

Citrus2011 [14]

Answer:

15.7

Step-by-step explanation:

3.14(5)

4 0

2 years ago

mark borrowed $125 from his dad to pay some bills. if he had already paid back $30 how much does he still owe

dedylja [7]

Answer:

$95

Step-by-step explanation:

It would be 125-30 which would give you 95 your welcome!

7 0

3 years ago

Read 2 more answers

When Klorina swims with the current, she swims 10 km in 2 h. Against the current, she can swim only 8 km in the same time. How f

nasty-shy [4]

Answer:

Klorina's rate in still water is 4.5 km/h

Current's rate is 0.5 km/h

Step-by-step explanation:

Let

x km/h = Klorina's rate in still water

y km/h = current's rate

With the current (current helps):

Distance = 10 km

Time = 2 hours

Rate = x + y km/h

$10=2(x+y)$

Against the current:

Distance = 8 km

Time = 2 hours

Rate = x - y km/h

$8=2(x-y)$

Divide both equations by 2:

$x+y=5\\ \\x-y=4$

Add these equations:

$x+y+x-y=5+4\\ \\2x=9\\ \\x=4.5\ km/h$

Subtract these two equations:

$(x+y)-(x-y)=5-4\\ \\x+y-x+y=1\\ \\2y=1\\ \\y=0.5\ km/h$

4 0

2 years ago