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Nostrana [21]
3 years ago
5

Need help with this math, learnt this today still very confused.

Mathematics
1 answer:
seraphim [82]3 years ago
6 0
The answer for 4 is 17.5 I’m pretty sure
You might be interested in
52.85 - 9.09 = what rounded to the nearest one
bonufazy [111]
52.85 - 9.09 rounded to the nearest one is 44
6 0
3 years ago
Ratiooo answer and working out pleaseee!! 18 points
miskamm [114]

Answer: 96 green pens sold

Step-by-step explanation:

Black = 3 pens

Red = 5 pens

Green = 6 pens

--

Black = 7 packs

Red = 2 packs

Green = 4 packs

--

Black = 3 x 7 = 21 total pens

Red = 5 x 2 = 10 total pens

Green = 6 x 4 = 24 total pens

Total units for total pens = 21 + 10 + 24 = 55u

55u = 220

1u = 220/55

    = 4

24u = 4 x 24

       = 96 green pens sold

--

96 green pens were sold.

3 0
3 years ago
Solve for x.
solmaris [256]

Answer:

x =-\frac{4}{5}

Step-by-step explanation:

x-\frac{1}{12} =-\frac{7}{20} \\\\   +\frac{1}{12}  +\frac{1}{12} \\\\x =-\frac{4}{5}

Hope this helps!

8 0
2 years ago
Find the area of the figure and round to the nearest hundredth
sweet [91]

Answer:

285.45

Step-by-step explanation:

If you multiply 17.3x16.5, you get 285.45, and when you round to the nearest hundredth, well, it gives you the same answer.

Therefore, the answer is 285.45.

5 0
3 years ago
1. Find the area of the region bounded above by y = e^x, bounded below by y = x, and bounded on the sides
salantis [7]

The area of the region bounded above by y= eˣ bounded by y = x, and bounded on the sides; x =0; and x = 1 is given as e¹ - 1.5.

<h3>What is the significance of "Area under the curve"?</h3>

This is the condition in which one process increases a quantity at a certain rate and another process decreases the same quantity at the same rate, and the "area" (actually the integral of the difference between those two rates integrated over a given period of time) is the accumulated effect of those two processes.

<h3>What is the justification for the above answer?</h3>

Area = \int\limits^1_0 {(e^x-x)} \, dx

= \int\limits^1_0 {e^x-x} \, dx - \int\limits^1_0 {(x)} \, dx

= e¹-(1/2-0); or

Area = e -1.5 Squared Unit

The related Graph is attached accordingly.

Learn more about area bounded by curve:
brainly.com/question/27866606
#SPJ1

3 0
2 years ago
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