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jok3333 [9.3K]
3 years ago
15

A hot air balloon starts at a height of 6 feet above the ground and then rises at a rate of 20 feet each minute. Which equation

gives the height h in feet as a function of time t in minutes? Oh=6t Oh = 20$ Oh=20t + 6 Oh=6+ 20​
Mathematics
1 answer:
Leni [432]3 years ago
6 0

Answer:

The height h it will travel in t minutes

Height h = 6 + 20(t)

Oh=20t + 6

Step-by-step explanation:

A hot air balloon starts at a height of 6 feet above the ground and then rises at a rate of 20 feet each minute.

Initial height h0 = 6 feet

Then it travel 29 feet each minute

Rate = 20 feet/ minute

The height h it will travel in t minutes

Height h = 6 + 20(t)

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Sphinxa [80]

Answer:

The density of the object is 0.1067 grams per cubic centimeter. (Rounded off to 4th decimal)

Step-by-step explanation:

Density = [Mass/Volume]

Here we have been given the dimensions of the object.

Volume = Height * Width * Length

Volume = 3.0cm*15.0cm*5.0cm

             =225cm^{3}

Now we can substitute the Mass and the Volume to the density equation.

Density = [Mass/Volume]

             =\frac{24grams}{225cm^{3} }

             =0.1067 grams per cubic centimeter. (Rounded off to 4th decimal)

4 0
3 years ago
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We need the actual problem/diagram or whatever to solve this

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Two angles are complementary. The measurement of ∠GHI is (5x+6)∘ and ∠JKL measures (3x+4)∘. What are the measures of the two ang
Alex777 [14]

Answer:

Angle GHI measures 56º, and angle JKL measures 34º.

Step-by-step explanation:

Complementary Angles:

If two angles are complementary, the sum of their measures is 90º.

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Since they are complementary:

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x = \frac{80}{8}

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Measures:

GHI: 5*10 + 6 = 50 + 6 = 56º

JKL: 3*10 + 4 = 30 + 4 = 34º.

Angle GHI measures 56º, and angle JKL measures 34º.

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