Answer:
20 dimes and 2 quarters
Step-by-step explanation:
x = number of dimes
y = number of quarters
minimum is greater than or equal to ≥
x+y ≥16
no more than is less than or equal to ≤ ,
value of dime is $ 0.10
value of quarter is $0.25 so
0.10x + 0.25y ≤ 3.00
Rewrite inequalities in terms of y:
y ≥16 - x
(0.25/0.25)y ≤ (3.00/0.25)-(0.10/0.25)x→
y≤12 - 0.4x
Graph system: see file
Answer:
1=1
2=4
3= <NTR=115
<RTM=45
<STN=45
4= A-124
B-45
C-45
D-90
E-124
5=15
6=?
Step-by-step explanation:
FGHJK
It's a simultaneous equation:
Steps:
1.Number the equations..
a+b=77 -1
a-b=13 -2
2. Choose what variable you want to use. In this case I would use the "b". Since the signs in front of the "b's" are different, add the two equations together
a + b = 77
+ + +
a (-b) = 13
Which gives;
2a = 90
Then solve to find a:
2a=90
a= 90/2
a=45
3.Then plug the "a" value into any of the original equations to find the "b" value. I would use equation 1 since the all the variables are positive.
a + b = 77
(45) + b = 77
b=77-45
b=32
4.Solution
a=45
b=32
A. is the correct one I did it on my test and got it right
Wow.... My brother Said that it took him a while to figure it out... but
add 110.25 and 55.45
you would get 165.70
multiply 165.70 by 4.5
then you would get 745.65
745.65 is your answer