Answer:
i need and image
Step-by-step explanation:
Take it bye 1)2 so it gives u ur anser so there u are
Answer:
This question is asking you to find the ending position of a shape (particle) that is moving horizontally along the horizontal axis by finding its velocity with the equation shown. When t=0, the shape is 4 units to the left of the vertical axis, so it wants you to find where on the horizontal axis the shape is when t = 8. Hope this helped!!!
Answer:
The measurement of arc AD is 53°
The measurement of arc BC is 39°
Step-by-step explanation:
Let
x----> the measurement of arc AD
y---> the measurement of arc BC
we know that
The measure of the internal angle is the semi-sum of the arcs comprising it and its opposite
so
m∠DEA=(1/2)[x+y]
substitute the value
46°=(1/2)[x+y]
92°=[x+y] -----> equation A
The measurement of the external angle is the semi-difference of the arcs which comprises
m∠P=(1/2)[x-y]
substitute the value
14°=(1/2)[x-y]
28°=[x-y] -----> equation B
Adds equation A and equation B
92°+14°=2x
x=106°/2=53°
Find the value of y
substitute in the equation A the value of x
92°=[53°+y]
y=92°-53°=39°
Answer:
Hi there! The square root would be 140.97517512.
Hope this helps! Brainliest appreciated!
