All categories

3 years ago

I realy need help im desperateNumber 37

Mathematics

2 answers:

Goryan [66]3 years ago

4 0

I just realized the numbers were in the negatives, sorry. The answer should be -4 > -22 because negative numbers work backwards on a number line. Sorry for any confusion.

stellarik [79]3 years ago

3 0

Im not sure what inequality means but it is 4°C<22°C

You might be interested in

In a particular triathlon the athletes cover 1/24 of the total distance by

pav-90 [236]

Answer:

15/8

Step-by-step explanation:

Let "d" be the total distance, that is, the distance for swimming (s), running (r) and going by bike (b).

d = s + r + b [1]

1/24 of the total distance is covered by swimming.

s = 1/24 d [2]

1/3 of the distance is covered by running.

r = 1/3 d [3]

If we replace [2] and [3] in [1], we get

d = 1/24 d + 1/3 d + b

b = d - 1/24 d - 1/3 d

b = 24/24 d - 1/24 d - 8/24 d

b = 15/24 d = 5/8 d

The ratio of the distance covered by bike to the distance covered by running is:

b/r = (5/8 d)/(1/3 d) = 15/8

5 0

3 years ago

Let f (x) = x^2 + 2xHow would you explain what f(5) means to a friend?

luda_lava [24]

Answer:

I would tell this friend to think of f(5) as them telling you what x is.

Step-by-step explanation:

So basically you would be imputing 5 everywhere x is to solve the equation.

7 0

3 years ago

Determine whether the equation is exact. If it is, then solve it. e Superscript t Baseline (7 y minus 3 t )dt plus (2 plus 7 e

umka21 [38]

Answer:

$F(t,y)=(2+7e^t)y+3(1-t)e^t +C$

Step-by-step explanation:

You have the following differential equation:

$e^t(7y-3t)dt+(2+7e^t)dy=0$

This equation can be written as:

$Mdt+Ndy=0$

where

$M=e^t(7y-3t)\\\\N=(2+7e^t)$

If the differential equation is exact, it is necessary the following:

$\frac{\partial M}{\partial y}=\frac{\partial N}{\partial t}$

Then, you evaluate the partial derivatives:

$\frac{\partial M}{\partial y}=\frac{\partial}{\partial t}e^t(7y-3t)\\\\\frac{\partial M}{\partial t}=7e^t\\\\\frac{\partial N}{\partial t}=\frac{\partial}{\partial t}(2+7e^t)\\\\\frac{\partial N}{\partial t}=7e^t\\\\\frac{\partial M}{\partial t} = \frac{\partial N}{\partial t}$