V=x³-7x+6, V=(x-2)(x+3)*h
(x-2)(x+3)*h=x³-7x+6
h{x²+x-6}=x³-7x+6
h=(x³-7x+6)/(x²+x-6)
Therefore h=x-1
-----------------------------
Check answer:
V=(x-2)(x+3)(x-1)
=(x-1)(x²+x-6)
=x(x²+x-6)-1(x²+x-6)
=x³+x²-6x-x²-x+6
=x³-6x-x+6
=x³-7x+6
Okay, start with the smaller square, you know the side length is 3 and that the width is 5, multiply this together:
3 * 5 = 15
That's the smaller left side of this shape, now the bigger side, divide the 10 yards at the bottom by 2 to properly represent the other side then multiply this by the 6 over there.
5 * 6 = 30
Conclusion for Area: After adding the results the answer should be 45.
The perimeter is solely adding all the sides together. You have a 10, two 5's, one 6, and two 3's. Add this together:
10 + 5 + 5 + 6 + 3 + 3 = 32
Conclusion for Perimeter: So the perimeter would be 32.
I hope this helps in someway, have a great rest of your day! ^ ^
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Answer:
5.81%
Step-by-step explanation:
The content of care package would be a board game and several snack packs.
Given is the weight of board game = 4 pounds.
The weight of one snack pack =
The total weight would be less than 25 pounds.
Solving for part A :
Let 'x' represents the number of snack packs.
So the weight of all snack packs would be 0.5x pounds.
Now weight of care pack = weight of board game + weight of all snack packs.
weight of care pack = 4 + 0.5x
But total weight must be less than 25 pounds.
So the inequality would be: 4 + 0.5x < 25
Solving for part B :
Solving the inequality 4 + 0.5x < 25
⇒ 4 + 0.5x - 4 < 25 - 4
⇒ 0.5x < 21
⇒ x < 42
Solving for part C :
Since x < 42 and x is an integer number, so x = 41.
She can include maximum of 41 snack packs in the care package.
Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719