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3 years ago

Plz help me with this

Mathematics

1 answer:

Setler79 [48]3 years ago

8 0

Answer: x = 8

(the correct answer was not provided as an option)

<u>Step-by-step explanation:</u>

$log_2(x-6)+log_2(x-4)=log_2(x)\\\\log_2[(x-6)(x-4)]=log_2(x)\\\\(x-6)(x-4)=x\\\\x^2-10x+24=x\\\\x^2-11x+24=0\\\\(x-3)(x-8)=0\\\\x=3\qquad x=8\\\\\\\text{The term after the log symbol (inside the parenthesis) must be greater than 0!}\\\\Check:\\3-6>0\ \text{FALSE --- so 3 is not a valid solution}\\\\8-6>0\ \text{TRUE}\\8-4>0\ \text{TRUE}\\8>0\ \text{TRUE --- 8 is a valid solution because it is true for all}$

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Answer:

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Step-by-step explanation:

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$y = mx+b$

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Given

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$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

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$m=-\frac{R}{P}$

Thus, the slope between (0, -R) and (−P, 0) is:

$m=-\frac{R}{P}$

We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

We are given the y-intercept point (0, −R).

Thus, y-intercept b = -R

so substituting b = -R and $m=-\frac{R}{P}$ in the slope-intercept form to determine the line of the equation

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As we know that the equation in the standard form is

Ax+By=C

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so converting into standard form

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Py = -Rx - PR

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Rx+Py = -Rx - PR + -Rx

Rx+Py = -PR

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Hello! :)

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--------------------------------------------------------------------------

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