Plz help me with this

Mathematics

1 answer:

Setler79 [48]3 years ago

8 0

Answer: x = 8

(the correct answer was not provided as an option)

<u>Step-by-step explanation:</u>

$log_2(x-6)+log_2(x-4)=log_2(x)\\\\log_2[(x-6)(x-4)]=log_2(x)\\\\(x-6)(x-4)=x\\\\x^2-10x+24=x\\\\x^2-11x+24=0\\\\(x-3)(x-8)=0\\\\x=3\qquad x=8\\\\\\\text{The term after the log symbol (inside the parenthesis) must be greater than 0!}\\\\Check:\\3-6>0\ \text{FALSE --- so 3 is not a valid solution}\\\\8-6>0\ \text{TRUE}\\8-4>0\ \text{TRUE}\\8>0\ \text{TRUE --- 8 is a valid solution because it is true for all}$

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ankoles [38]

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Step-by-step explanation:

7 0

2 years ago

3 3/4 -1 3/14 in simpilist form

lakkis [162]

For this case we must simplify the following expression:

$3 \frac {3} {4} -1 \frac {3} {14} =$

To do this, we convert the mixed numbers to improper fractions:

$\frac {4 * 3 + 3} {4} - \frac {14 * 1 + 3} {14} =\\\frac {15} {4} - \frac {17} {14} =\\\frac {14 * 15-4 * 17} {4 * 14} =\\\frac {210-68} {56} =\\\frac {142} {56} =\\\frac {71} {28} =\\2 \frac {15} {28}$