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2 years ago

A number is at most 0 and greater then -10 the least possible integer value of the number is

2 answers:

7 0

The least possible integer value of the number of -10 is most likely less than that number so anything less than that number would be the answer

OLEGan [10]2 years ago

7 0

I’m pretty sure it’s -9

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if the heart of an elephant , at rest beat an average of 1680 beats in 60 min . What is the rate in beats per minute

Tresset [83]

Use the rule of 3 simple

1680 beats ------- 60 min.
x beats -------------- 1 min.
----------------------------------
x = (1680*1)/60 = 1680/60 = 168/6 = 28 beats per minute

hope helped

5 0

3 years ago

Is P - 1 upon p = 4 find P + 1 upon p whole square

zlopas [31]

Given that (p - 1/p) = 4, the value of p² + 1/p² is 18. Detail below

<h3>Data obtained from the questio</h3>

(p - 1/p) = 4
p² + 1/p² = ?

<h3>How to determine the value of p² + 1/p²</h3>

(p - 1/p) = 4

Square both sides

(p - 1/p)² = (4)²

(p - 1/p)² = 16 ....(1)

Recall

(a - b)² = a² + b² - 2ab

Thus,

(p - 1/p)² = p² + 1/p² - (2 × p × 1/p)

(p - 1/p)² = p² + 1/p² - 2

From equation (1) above,

(p - 1/p)² = 16

Therefore,

p² + 1/p² - 2 = 16

Rearrange

p² + 1/p² = 16 + 2

p² + 1/p² = 18

Thus, the value of p² + 1/p² is 18

Learn more about algebra:

brainly.com/question/953809

#SPJ1

6 0

1 year ago

What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

<u>Find the length of the segment DC</u>

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

<u>the answer is</u>

$BC=31.2\ units$

8 0

2 years ago

Read 2 more answers

Pls help how do i solve for x in this equation??

evablogger [386]

Answer:

x = -2

Step-by-step explanation:

1. Square both sides
x^2 +3x + 6 = x^2
2. Subtract x^2 from both sides
3x + 6 = 0
3. Subtract 6 from both sides and divide by 3
x = -2

6 0

1 year ago

A triangular prism is shown in the diagram.

qaws [65]

Answer:

246 cm^3

Step-by-step explanation:

See attached image.

8 0

2 years ago