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Bezzdna [24]
2 years ago
14

Reduce the Fractions 15/9to its Lowest Terms

Mathematics
1 answer:
KatRina [158]2 years ago
6 0

\large\bf{\red{  \implies}} \tt \:   \cancel\frac{15}{9}   \\

\large\bf{\red{  \implies}} \tt \:   \frac{5}{3}  \\

Decimal Form - 1.6667

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A small theater with 200 seats sells two kinds of tickets for a performance. Premium tickets sell for $20 each and Standard tick
KATRIN_1 [288]
P + s = 200......p = 200 - s
20p + 15s = 3400

20(200 - s) + 15s = 3400
4000 - 20s + 15s = 3400
-20s + 15s = 3400 - 4000
-5s = - 600
s = -600/-5
s = 120 <=== there were 120 standard tickets sold

p + s = 200
p + 120 = 200
p = 200 - 120
p = 80 <=== there were 80 premium tickets sold
7 0
3 years ago
If f(x) = 5x + 4, which of the following is the inverse of Ax)?
Levart [38]

Answer:

f^{-1} (x) = \frac{x-4}{5}

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 5x + 4 ( subtract 4 from both sides )

y - 4 = 5x ( divide both sides by 5 )

\frac{y-4}{5} = x

change x to f^{-1}(x) and y back to x, thus

f^{-1}(x) = \frac{x-4}{5}

6 0
3 years ago
What is the product of 2x + y and 5x – y + 3?
hoa [83]

Answer:  The required product is 10x^2-y^2+3xy+6x+3y.

Step-by-step explanation:  We are to find the product f the following two algebraic expressions:

E_1=2x+y,\\\\E_2=5x-y+3.

To find the product of the above two expressions, we must multiply each term of the first expression with each term of the second expression.

The multiplication is as follows:

M\\\\=E_1 \times E_2\\\\=(2x+y)\times(5x-y+3)\\\\=10x^2-2xy+6x+5xy-y^2+3y\\\\=10x^2-y^2+3xy+6x+3y.

Thus, the required product is 10x^2-y^2+3xy+6x+3y.

7 0
2 years ago
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Katyanochek1 [597]

Answer: B

Step-by-step explanation:

You have the same bases, so you can just focus on the exponents.

The difference between 5 and -1 is 6, therefore, the answer is B.

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Please answer the image below
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Answer:

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Step-by-step explanation:

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