So a deckameter is = to 10 meters
just multiply it
3*10= 30
then divide
30/1= 30
So glenn needs 30 meter paces of ribbon
You need to use Pythagoras’ Theorem.
A² + B² = c² and c is the hypotenuse of the right angled triangle.
The height of the tower (5 feet) is A and the distance from the end of the cable and the base of the tower (12 feet) is B. The length of ONE cable is c. So:
A² + B² = c²
5² + 12² = c²
25 + 144 = c²
169 = c²
13 = c. This is the length of one cable.
3 x 13 = 39 therefore the total length of the cables is 39 feet.
25
you can use long division to do this:-
a + 3 ) a^2 + 2a + 3
= a - 1 remainder 6 or you can write it as a - 1 + 6 / (a + 3)
Answer:
111
Step-by-step explanation:
It is given that the student to faculty ratio at a small college is 17:3.
Let number of students and faculty members are 17x and 3x respectively.
It is given that total number of students and faculty is 740.
Divide both sides by 20.
Number of student 
Number of faculty members 
Therefore, there are 111 faculty members at the college.
Answer:
11 0ver 54
Step-by-step explanation:
