Question

Help me it’s urgent

Answer 1

Answer:

$a_1 = -\dfrac{3}{4}$

Step-by-step explanation:

$a_1 \times r = a_2$

$a_1 \times r^2 = a_3$

$a_1 \times r^3 = a_4$

...

$a_1 \times r^8 = a_9$

$\dfrac{a_9}{a_4} = \dfrac{a_1 \times r^8}{a_1 \times r^3} = \dfrac{-196}{6}$

$r^5 = -32$

$r = -2$

$a_1 \times r^3 = a_4$

$a_1 \times (-2)^3 = 6$

$a_1 = \dfrac{6}{-8}$

$a_1 = -\dfrac{3}{4}$