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4 years ago

How do I do problems 4-6

Mathematics

1 answer:

faltersainse [42]4 years ago

4 0

4-6= -2 what are you having problems understanding I can help

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Select the correct answer

Kitty [74]

Answer:

(4,-7)

Step-by-step explanation:

-w=(5,-3)

-z=(-1,-4)

so -w-z=(5-1,-3-4)

4 0

3 years ago

Determine the number of units of solution 2 required to obtain the desire percent alcohol concentration of the final solution. T

KiRa [710]

Answer:

0.66 gal.

Step-by-step explanation:

The following should apply:

C1 * V1 = C2 * V2

we have that C1 is 0.1, that C2 is 0.3 and that V1 is equal to 2 gal

replacing the values we have that:

0.1 * 2 = 0.3 * V2

reorganizing the equation we have:

V2 = 0.1 * 2 / 0.3 solving this remains 0.66.

It means that the amount of solution 2 is 0.66 gal.

8 0

4 years ago

Solve the equation by using the quadratic formula. x^2+2x=6

katrin [286]

Answer:

$\Huge \boxed{{x=-1\pm \sqrt{7}}}$

Step-by-step explanation:

x² + 2x = 6

Subtract both sides by 6.

x² + 2x - 6 = 0

ax²+bx+c=0

a=1, b=2, and c=-6

We can apply the quadratic formula.

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plug in the values.

$\displaystyle x=\frac{-2\pm\sqrt{2^2-4(1)(-6)}}{2(1)}$

Evaluate.

$\displaystyle x=\frac{-2\pm\sqrt{4-(-24)}}{2}$

$\displaystyle x=\frac{-2\pm\sqrt{28}}{2}$

$\displaystyle x=\frac{-2\pm 2\sqrt{7}}{2}=-1 \pm \sqrt{7}$

6 0

3 years ago

Espress the following in standard form 24.12<br><br><br>

ANTONII [103]

Answer: 2412(-2)
(-2)- small numbers

Explanation: you would divide (due to it being a negative 2) by two 10s to get your original number

5 0

3 years ago

Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th

Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 21-1 = 20$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have $T = 2.528$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{0.40}{\sqrt{21}} = 0.0873$

Now, we multiply T and s

$M = 2.528*0.0873 = 0.2207$

Then

The lower end of the interval is the mean subtracted by M. So:

$L = 3.27 - 0.2207 = 3.0493$

The upper end of the interval is the mean added to M. So:

$LCL = 3.27 + 0.2207 = 3.4907$

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0

3 years ago