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vichka [17]
3 years ago
10

NADH and FADH2 are both electron carriers that donate their electrons to the electron transport chain. The electrons ultimately

reduce O2 to water in the final step of electron transport. However, the amount of ATP made by electrons from an NADH molecule is greater than the amount made by electrons from an FADH2 molecule. Which statement best explains why more ATP is made per molecule of NADH than per molecule of FADH2? a) The H+ gradient made from electron transport using NADH is located in a different part of the mitochondrion than the H+ gradient made using FADH2. b)Fewer protons are pumped across the inner mitochondrial membrane when FADH2 is the electron donor than when NADH is the electron donor. c)It takes more energy to make ATP from ADP and Pi using FADH2 than using NADH. d)There is more NADH than FADH2 made for every glucose that enters cellular respiration. e)FADH2 is made only in the citric acid cycle while NADH is made in glycolysis, acetyl CoA formation, and the citric acid cycle.
Chemistry
1 answer:
Sladkaya [172]3 years ago
3 0
<h3><u>Answer;</u></h3>

B. Fewer protons are pumped across the inner mitochondrial membrane when FADH2 is the electron donor than when NADH is the electron donor.

<h3><u>Explanation</u>;</h3>
  • NADH and FADH2 are two important electron carriers in the cellular respiration process.
  • NADH is a high-energy electron carrier that is reduced during glycolysis, pyruvate processing, and the citric acid cycle, and which carries electrons to the electron transport system.
  • The electron transport chain passes electrons from NADH and FADH2 to protein complexes and mobile electron carriers.
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3. In an experiment it was found that 40.0cm of 0.2M sodium hydroxide solution just neutralized 0.2g
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The relative molecular mass of acid A : 50 g/mol

<h3>Further explanation</h3>

Given

40.0 cm³(40 ml) of 0.2M sodium hydroxide

0.2g  of a dibasic acid

Required

the relative molecular mass of acid A

Solution

Titration formula

M₁V₁n₁=M₂V₂n₂

n=acid/base valence(number of H⁺/OH⁻)

NaOH ⇒ n = 1

Dibasic acid =  diprotic acid (such as H₂SO₄)⇒ n = 2

mol = M x V

Input the value in the formula :(1 = NaOH, 2=dibasic acid)

0.2 x 40 x 1 = M₂ x V₂ x 2

M₂ x V₂ = 4 mlmol = 4.10⁻³ mol ⇒ mol of Acid A

The relative molecular mass of acid A (M) :

\tt M_A=\dfrac{mass }{mol}=\dfrac{0.2~g}{4.10^{-3}}=50~g/mol

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What is the basis for the classification of changes in matter into physical and chemical changes quizlet
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Explanation:

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Answer:

Explanation:

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Metallicity is a measure of the tendency of atoms of an element to lose electrons.

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Down a periodic group, metallicity increases.

b.

Across a period from left to right electropositivity or metallicity decreases.

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