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7nadin3 [17]
3 years ago
8

Balancee por tanteo las siguientes ecuaciones químicas. Escriba el nombre a reactantes y productos. H2O5 + H2O ---> HNO3 Na2O

+ OH2O --> ONaOH
Chemistry
1 answer:
Elan Coil [88]3 years ago
3 0

Answer:

a. N₂O₅ + H₂O ⇒ 2 HNO₃ (pentóxido de dinitrógeno + agua ⇒ ácido nítrico)

b. Na₂O + H₂O ⇒ 2 NaOH (óxido de sodio + agua ⇒ hidróxido de sodio)

Explanation:

Tenemos que balancear, por el método de tanteo, las siguientes ecuaciones químicas.

a. En la primera reacción, el pentóxido de dinitrógeno reacciona con agua para formar ácido nítrico. Es una reacción de síntesis o combinación.

N₂O₅ + H₂O ⇒ HNO₃

Podremos obtener la ecuación balanceada si multiplicamos HNO₃ por 2.

N₂O₅ + H₂O ⇒ 2 HNO₃

b. En la segunda reacción, óxido de sodio reacciona con agua para formar hidróxido de sodio. Es una reacción de síntesis o combinación.

Na₂O + H₂O ⇒ NaOH

Podremos obtener la ecuación balanceada si multiplicamos NaOH por 2.

Na₂O + H₂O ⇒ 2 NaOH

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For the equilibrium
sleet_krkn [62]

Answer:

\large \boxed{\text{0.091 atm }}

Explanation:

The balanced equation is

I₂(g) + Br₂(g) ⇌ 2IBr(g)

Data:

   Kc = 8.50 × 10⁻³

n(IBr) = 0.0600 mol

     V = 1.0 L

1. Calculate [IBr]

\text{[IBr]} = \dfrac{\text{0.0600 mol}}{\text{1.0 L}} = \text{0.0600 mol/L}

2. Set up an ICE table.

\begin{array}{ccccccc}\rm \text{I}_{2}& + & \text{Br}_{2} & \, \rightleftharpoons \, & \text{2IBr} &  &  \\0 & & 0 & &0.0600 & & \\+x &  & +x &   &- 2x & & \\x &   & x &   & 0.0600 - 2x & & \\\end{array}

3. Calculate [I₂]

\begin{array}{rcl}K_{\text{c}}&=&\dfrac{\text{[IBr]}^{2}} {\text{[I$_{2}$][Br]$_{2}$}}\\\\8.50 \times 10^{-2}&=&{\dfrac{(0.0600 - 2x)^{2}}{x^{2}}}& &\\\\0.2915x & = &{\dfrac{0.0600 - 2x}{x}}& &\\\\0.2915x & = &0.0600 - 2x\\\\2.2915x & = & 0.0600\\x & = & \textbf{0.026 18 mol/L}\\\end{array}\\

4. Convert the temperature to kelvins

T = (150 + 273.15) K = 423.15 K

5. Calculate p(I₂)

\begin{array}{rcl}\\pV & = & nRT\\p & = & cRT\\p & = & \text{0.026 18 mol} \cdot \text{L}^{-1}\times \text{0.082 06 L} \cdot \text{atm} \cdot \text{K}^{-1} \text{mol}^{-1} \times \text{423.15 K}\\& = & \textbf{0.91 atm}\\\end{array}\\\text{The partial pressure of iodine is $\large \boxed{\textbf{0.91 atm}}$}

6 0
3 years ago
Which best characterizes a crystal
Pachacha [2.7K]
<h3><u>Answer;</u></h3>

A dense substance that is hard and incompressible

<h3><u>Explanation</u>;</h3>
  • <em><u>Crystals are solids that are made up of particles such as molecules, atoms or ions, </u></em>which are arrange in a highly ordered microscopic structure, forming a crystal lattice which extends in all directions.
  • Examples of crystals include<em><u> quartz,</u></em> that is made up of silicon (iV) oxide molecules that are arranged in a lattice,<u><em>table salt</em></u> is another example that is made up of sodium and chloride ions that are arranged in a lattice
  • Crystals are very ordered, they may be made up of atoms of the same elements or atoms of different elements such as in the case of table salt.
5 0
3 years ago
Read 2 more answers
explain why elements lying on the extreme right of the periodic table as from non metals but those lying on the extreme left a s
kvasek [131]
Element at Extreme Left In Periodic Table:
                                                                   The elements of Group I-A (1) are present at extreme left of the periodic table. They are called as Alkali Metals. Alkali Metals are strong metals. These elements can easily loose their valence electron. The valence shell electronic configuration of these elements is,

                                                     ns¹

where n is principle quantum number, which shows main energy level or shell. These metals can gain Noble gas configuration (stable configuration) either by loosing one electron or by gaining seven or more electrons. As it is quite reasonable to loose one electron instead of gaining seven or more electrons so these element easily loose one electron to gain noble as configuration. The Metallic character decreases along the period from left to right. So Group II-A (2) are second most metallic elements and so on. These metals at extreme left mainly exist in solid form.

Element at Extreme Right In Periodic Table:
                                                                     Elements present at extreme right of the periodic table lacks the properties of metallic character and act as non-Metals. They have almost complete outermost shell or have the deficiency of one or two electrons. They are not as hard as metallic elements and they exist with complete octet like in Noble gases, or deficient with one electron (Halogens) or two electrons (oxygen group). These elements tend to gain or accept electron if their valence shell is deficient with required number of elements. Like the valence electronic configuration of Halogens is,

                                                   ns², np⁵

So, Halogens readily accept one electron and attain noble gas configuration. Elements at extreme left exist mainly in gas phase.
5 0
3 years ago
Magnesium has three naturally occurring isotopes, ²⁴Mg (isotopic mass = 23.9850 amu, abundance = 78.99%), ²⁵Mg (isotopic mass =
joja [24]

The atomic mass of the  magnesium is : 24.31⋅g.

<h3>What is isotopes?</h3>

Isotopes are members of a family of elements that all have the same number of protons and different numbers of neutrons. The number of protons in the nucleus determines the atomic number of an element on the periodic table.

Magnesium has three natural isotopes: ²⁴Mg, ²⁵Mg, and ²⁶Mg.

<h3>What is atomic mass ?</h3>

Atomic mass is the mass of an atom. The SI unit of mass is the kilogram, while atomic mass is often expressed in the non-SI unit dalton (synonymous with uniform atomic mass unit). 1 Da is defined as 1/12 the mass of a free carbon-12 atom at rest in the ground state.

Calculation :

The atomic mass is the weighted average of the individual isotopic masses:

(23.99×78.99%+24.99×10.00%+25.98×11.01%)⋅g=24.31⋅g

To know more atomic mass please click here : brainly.com/question/338808

#SPJ4

4 0
1 year ago
If 35.0 mL of water in a graduated cylinder is displaced by 8.00 mL
sdas [7]

Answer:

<h2>0.52 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}\\

From the question

volume = final volume of water - initial volume of water

volume = 35 - 8 = 27 mL

We have

density =  \frac{14}{27}  \\  = 0.518518...

We have the final answer as

<h3>0.52 g/mL</h3>

Hope this helps you

3 0
3 years ago
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