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Sav [38]
2 years ago
10

What has modern media shown you about atoms

Chemistry
2 answers:
mash [69]2 years ago
8 0
Atoms like in chemistry class?
klasskru [66]2 years ago
8 0
What do you. Mean by that
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Graph the circle which is centered at (4,4)(4,4)left parenthesis, 4, comma, 4, right parenthesis and has a radius of 3 units.
OleMash [197]

Answer:

i dont know the answer sorry

7 0
3 years ago
help me on the bottom pleaseeeeeeee also please check the top BUT I NEED HELP OM THE BOTTOM TAJNKSKSKSLSLSLALS GOOODD BLESSS UUU
Yanka [14]
Because when you take the sand out it doesn't stay the same shape
3 0
3 years ago
How much water (H2O ) would form if 4.04 g of hydrogen (H2) reacted with 31.98 g of oxygen (O2 )?
Norma-Jean [14]

Answer:

Mass = 36 g

Explanation:

Given data:

Mass of water formed = ?

Mass of hydrogen = 4.04 g

Mass of oxygen = 31.98 g

Solution:

Chemical equation:

2H₂ + O₂   →   2H₂O

Number of moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 4.04 g/ 2 g/mol

Number of moles = 2.02 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 31.98 g/ 32 g/mol

Number of moles = 1.0 mol

Now we will compare the moles of water with hydrogen and oxygen.

                O₂         :         H₂O

                 1           :           2

                H₂         :         H₂O

                 2          :          2

               2.02       :      2.02

Number of moles of water formed by oxygen are less thus oxygen will limiting reactant.

Mass of water:

Mass = number of moles × molar mass

Mass = 2 mol × 18 g/mol

Mass = 36 g

8 0
2 years ago
Is o3 inorganic or organic
sammy [17]

Answer:

I'm not sure but I think it's organic

6 0
3 years ago
Read 2 more answers
At 333 k, which of the pairs of gases below would have the most nearly identical rates of effusion?
rjkz [21]
E. co and n2Effusion is the process where gas escapes through a hole. Gases with a lower molecular mass effuse more speedy than gases with a higher molecular mass. R<span>elative rates of effusion is related to the molecular mass.
a) M(N</span>₂)/M(O₂) = 28/32 = 0,875
b) M(N₂O)/M(NO₂) = 44/46 = 0,956
c) M(CO)/M(CO₂) = 28/44 = 0,636
d) M(NO₂)/M(N₂O₂) = 44/58= 0,758
e) M(CO)/M(N₂) = 28/28 = 1, <span>CO and N</span>₂ <span>have iexact molecular masses and will effuse at nearly identical rates.</span>
8 0
3 years ago
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