No they have eukaryotic cells
Answer:
611.064 kJ
Explanation:
Given :
m = 200 mL = 200 g
Specific heat of ice = 2.06 J/g°C
Q = mcΔt
Δt = 0 - (-22) = 22
Q1 = 200 * 2.06 * 22 = 9064 J
Q2 = Melt 0 °C solid ice into 0 °C liquid water:
Q2 = m · ΔHf ; ΔHf = heat of fusion of water = 334j/g
Q2 = 200 * 334 = 66800 J
Q3 : Heat to convert from 0°C to 100°C
Q3 = mcΔt ; c = 4.19 J/g°C ; Δt = (100 - 0) = 100
Q3 = 200 * 4.19 * 100 = 83800 J
Q4: heat required to boil water to steam
Q = m · ΔHv
Hv = heat of vaporization of water = 2257 J/g
Q4 = 200 * 2257 = 451400 J
Total Q = Q1 + Q2 + Q3 + Q4
Q = 9064 + 66800 + 83800 + 451400
Q = 611,064 Joules
Q = 611.064 kJ
H's result was one dead flower ... not surprising ... stuck in a dark room = no photosynthesis = no growth = death.
H loses is "control" part of his "experiment".
Q gives no idea the colour of H's flowers in expt.
H "shows" that a watered plant in sunlight with a bit of fetilizer tends to grow. He could have had a look outside at a garden to see that.
improvement by not killing the "control" plant. put it side by side with the test plant, so both get the photo stuff. Then measured fertilizer in test plant, and same water minus fert in control.
As for the colour I've no idea.
There are 3 types of faults, strike-slip fault, normal fault and reverse fault. So choices a and d will no longer be considered. Now the difference between a normal fault and a reverse fault is in a normal fault the hanging wall moves downwards and in a reverse fault the hanging wall moves upwards.
So considering the two faults and their characteristics, the answer would be b. reverse fault.
I solved it and got 374.2N so i would put 375N
sorry i didn’t get any of the ones on there, i probably made a mistake.
