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Alexxandr [17]
3 years ago
12

If you needed information about a scientificconcept, whom would you ask? Check all thatapply.my teachermy parentsa university pr

ofessora scientistmy friendsa librarian

Physics
2 answers:
ycow [4]3 years ago
7 0
It's possible that you could get the information you need from ANY of them. 
But it's true that if you need the info in a hurry, and it absolutely positively
has to be correct, then you should approach them in kind of the order of
what the probability is that you'll get the straight, correct story.

To me, here's how I would line them up in the order of probability:

Tops:  a scientist specializing in that particular field
next    a scientist specializing in a different field
next    a university professor who teaches that particular field
next    a university professor who teaches a different field
next    a librarian, who may not know it but definitely knows where to find it  
next    my parents
next    my teacher
last     my friends  (nothing against my friends, but if it has to be fast
                             and accurate, then I may not have the time to wait
                             for my friend to find it, or the time to check it out
                             after I get it from my friend)
allochka39001 [22]3 years ago
4 0
A librarian... it might also be a scientist
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Answer: Impulse = 4 kgm/s

Explanation:

From the question, you're given the following parameters:

Momentum P1 = 12 kgm/s

Momentum P2 = 16 kgm/s

Time t = 0.2 s

According to second law of motion,

Force F = change in momentum ÷ time

That is

F = (P2 - P1)/t

Cross multiply

Ft = P2 - P1

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Impulse = 16 - 12 = 4 kgm/s

The magnitude of the impulse is therefore 4 kgm/s.

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Bingel [31]
The horizontal force is m*v²/Lh, where m is the total mass. The vertical force is the total weight (233 + 840)N. 

<span>Fx = [(233 + 840)/g]*v²/7.5 </span>

<span>v = 32.3*2*π*7.5/60 m/s = 25.37 m/s </span>

<span>The horizontal component of force from the cables is Th + Ti*sin40º and the vertical component of force from the cable is Ta*cos40º </span>

<span>Thh horizontal and vertical forces must balance each other. First the vertical components: </span>

<span>233 + 840 = Ti*cos40º </span>

<span>solve for Ti. (This is the answer to the part b) </span>

<span>Horizontally </span>

<span>[(233 + 840)/g]*v²/7.5 = Th + Ti*sin40º </span>

<span>Solve for Th </span>

<span>Th = [(233 + 840)/g]*v²/7.5 - Ti*sin40º </span>

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It’s 53:) Or - quit

Explanation:

That’s my strong streak

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