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3 years ago

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A type of star called a red dwarf gets its name because it is a relatively small star that appears redder than the Sun when view

ed through a telescope. Red dwarfs, therefore, _____ more red light than stars like the Sun. A. emit B. reflect C. absorb D. transmit

1 answer:

weeeeeb [17]3 years ago

5 0

Answer:

option (b) reflect

make me brainliest

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Which statement describes a digital signal used to store information?

velikii [3]

Answer:

D. It is easy to copy.

Explanation:

It is not B, or A, nor C.

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2 years ago

For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The larg

viva [34]

Answer:

The magnetic field is 1.16 T.

Explanation:

speed, v = 10% of speed of light = 3 x 10^7 m/s

diameter, d = 54 cm

radius, r = 0.27 m

charge, q = 1.6 x 10^-19 C

mass, m = 1.67 x 10^-27 kg

Let the magnetic field is B.

The centripetal force is balanced by the magnetic force.

$qvB=\frac{mv^2}{r}\\\\B =\frac{mv}{qr}\\\\B =\frac{1.67\times 10^{-27}\times 3\times 10^{7}}{1.6\times 10^{-19}\times 0.27}\\\\B =1.16 T$

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2 years ago

Help.me on question 3 pls as fast as you can

antoniya [11.8K]

Answer:

Drought

Explanation:

If you are asking about Number 2. then the answer would be lack of precipitation (rain).

Climate change didn't allow for cold air to meet the warm air to produce precipitation over the run off area of the lake.

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3 years ago

If force remains constant and acceleration decreases what must happen to the mass

blondinia [14]

That can only be happening if the mass mysteriously increased somehow. I'd like to know how in the world THAT happened.

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3 years ago

A 20 kg wagon is rolling to the right across a floor. A person attempts to catch and stop the crate and applies a force of 70 N,

Serggg [28]

Answer:

1.736m/s²

Explanation:

According to Newton's second law;

$\sum F_x = ma_x\\$

$Fm - Ff = ma_x\\$ where;

Fm is the moving force = 70.0N

Ff is the frictional force acting on the body

$Ff = \mu R\\Ff = \mu mg\\$

$\mu$ is the coefficient of friction

m is the mass of the object

g is the acceleration due to gravity

a is the acceleration/deceleration

The equation becomes;

$Fm - Ff = ma_x\\Fm - \mu mg = ma\\$

Substitute the given parameters

$Fm - \mu mg = ma\\70 - 0.18(20)(9.8) = 20a\\70-35.28 = 20a\\34.72 = 20a\\a = \frac{34.72}{20}\\a = 1.736m/s^2\\$

Hence the deceleration rate of the wagon as it is caught is 1.736m/s²

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3 years ago