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Olenka [21]
3 years ago
13

Find the length of WY.

Mathematics
1 answer:
Rzqust [24]3 years ago
6 0

Answer:

9

Step-by-step explanation:

might be wrong, but i have so little information

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Really easy! PLEASE HELP, I Will mark Brainliest
zlopas [31]

Answer:

(x,y)=(-5,5)

Step-by-step explanation:

7 0
3 years ago
Sixty-three people participated in a study to see if they were left-brain dominant or right-brain dominant. In the study, the pe
fgiga [73]
The two-way table is attached.

We know that 63 people took the survey, and 22 of them were left-handed.  This means that 63-22=41 of them are right handed.

Out of the 63 total, 37 are left brain dominant; this means that 63-37=26 are right brain dominant.

Of the 26 that are right brain dominant, 21 are right handed; this means 26-21=5 are left handed.

Of the 22 left-handed people, 5 are right brain dominant; this means 22-5 = 17 are left brain dominant.

Of the 37 left brain dominant people, 17 are left handed; this means 37-17=20 are right handed.

8 0
3 years ago
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I require someone to answer this question for me ASAP please?
elixir [45]

Answer:

x has to be less than 3

Step-by-step explanation:

3 0
3 years ago
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How to solve for 6x-12+2x=3+8x-15
Alecsey [184]
6x−12+2x=3+8x−15

Simplify:

6x+−12+2x=3+8x+−15

(6x+2x)+(−12)=(8x)+(3+−15)(Combine Like Terms)

8x+−12=8x+−12


8x−12=8x−12

Subtract 8x from both sides.

8x−12−8x=8x−12−8x

−12=−12

Add 12 to both sides.

−12+12=−12+12

0=0

The real numbers are the only solution we can have.


4 0
3 years ago
What is the standard form of the linear function that passes
babunello [35]

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{4}}}\implies \cfrac{-3}{-2}\implies \cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{4})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2(y-1)=2\left( \cfrac{3}{2}(x-4) \right)}\implies 2y-2 = 3(x-4)\implies 2y-2=3x-12 \\\\\\ -3x+2y-2=-12\implies -3x+2y=-10\implies \stackrel{\times -1\textit{ to both sides}}{3x-2y=10}

7 0
2 years ago
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