When the temperature of a gas changes, it's volume decreases from 12 cm3 to 7 cm3 if the final temperature is measured to be 18°
1 answer:
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Given:
n = 12 moles of oxygen
T = 273 K, temperature
p = 75 kPa, pressure
Use the ideal gas law, given by
where
V = volume
R = 8.3145 J/(mol-K), the gas constant
Therefore,
Answer: 0.363 m³
n = 12 moles of oxygen
T = 273 K, temperature
p = 75 kPa, pressure
Use the ideal gas law, given by
where
V = volume
R = 8.3145 J/(mol-K), the gas constant
Therefore,
Answer: 0.363 m³
Answer:
(a) Increasing the temperature adds heat which is a reactant shifting the equilibrium rightwards.
(b) Pressure has no effect since the change in the number of moles is zero.
Explanation:
Hello,
In this case, one could represent the given reaction as:
Since it is endothermic. Thus, solving the (a) statement, one identifies the heat as a reagent, that is why the reaction cools down as it progress, therefore, by increasing the temperature, heat is added, that is, a reagent is added, which shifts the equilibrium rightwards, in other words, more NO is produced so its concentration increases.
Furthermore, for the (b) statement, since the change in the number of moles is zero, based on the stoichiometric coefficients as shown below:
Such value implies that the pressure has no effect on the concentration, taking into account the following form of the law of mass action:
Thus, since ,
, so no effect in concentration is due to the pressure.
Best regards.