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3 years ago

Write a balanced chemical equation for the standard formation reaction of gaseous formaldehyde CH2O

1 answer:

5 0

From the combustion of octane, the formaldehyde will be formed as this equation:

C8H18 + O2 → CH2O + H2O this is the original equation but it is not a balanced equation, so let's start to balance it:

the equation to be balanced so the number of atoms on the right side of the equation sholud be equal with the number of atoms on the lef side.

-we have 8 C atoms on left side and 1 atom on the right side so we will try putting 8 CH2O on the right side instead of CH2O

C8H18 + O2 → 8 CH2O + H2O

we have 2 O atoms on the left side and 9 atoms on the right side so we will try first to put 9 O2 instead of O2 on the left side and put 2H2O on the right side and put 16 CH2O instead of 8 CH2O to make the atoms of O are equal on both sides = 18 atoms

C8H18 + 9 O2 → 16 CH2O + 2H2O

put now we have 8 atom C on the left side and 16 atom on the right side so, we will put 2 C8H18 instead of C8H18 now we get this equation:

2C8H18 + 9O2 →16 CH2O + 2H2O

-now we have 36 of H atoms on both sides.

- and 16 of C atoms on both sides.

- and 18 of O atoms on both sides.

now all the number of atoms of O & C & H are equal on both sides

∴ 2C8H18 + 9O2 → 16 CH2O + 2 H2O

is the final balanced equation for the formation of formaldehayde

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How many molecules are in 1.28 mols of silicon dioxide

coldgirl [10]

Answer:

7.71x10^23 molecules

Explanation:

Avogadro's # = 6.022x10^23

1.28 mol SiO2 x 6.022x10^23/ 1 mol SiO2 = 7.71x10^23 molecules

8 0

2 years ago

fish tank initially contains 35 liters of pure water. Brine of constant, but unknown, concentration of salt is flowing in at 5 l

weeeeeb [17]

Answer:

Therefore, the rate of change in the amount of salt is $\frac{dx}{dt} =( 5c}{ - \frac{x }{20})$

$\frac{grams }{min}$

Explanation:

Given:

Initial volume of water $V = 35$ lit

Flowing rate = 5 $\frac{Lit}{min}$

The rate of change in the amount of salt is given by,

$\frac{dx}{dt} =$ ( Rate of salt enters tank - rate of sat leaves tank )

Since tank is initially filled with water so we write that,

$x(0) = 0$

Let amount of salt in the solution is $c$ ,

$\frac{dx}{dt} = \frac{5c}{1 } - \frac{x(t) \times 5}{100}$

$\frac{dx}{dt} =( 5c}{ - \frac{x }{20})$ $\frac{grams}{min}$

Therefore, the rate of change in the amount of salt is $\frac{dx}{dt} =( 5c}{ - \frac{x }{20})$

$\frac{grams }{min}$

7 0

3 years ago

What fraction can be used in conversion of 32 m3 to mm3

zimovet [89]

The calculation is (Measurement in m³ x 1000³)

Therefore

Measurement in m³ x 1 000 000

Its not a fraction as there are 1000mm in a m, so to convert from m to mm you must multiply

5 0

2 years ago

Read 2 more answers

Calculate the number of sodium ions, perchlorate ions, Cl atoms and O atoms in 17.8 g of sodium perchlorate. Enter your answers

Degger [83]

17.8 g of sodium perchlorate contains 8.73 × 10²² Na⁺ ions, 8.73 × 10²² ClO₄⁻ ions, 8.73 × 10²² Cl atoms and 3.49 × 10²³ O atoms.

First, we will convert 17.8 g of NaClO₄ to moles using its molar mass (122.44 g/mol).

$17.8 g \times \frac{1mol}{122.44g} = 0.145 mol$

Next, we will convert 0.145 moles to molecules of NaClO₄ using Avogadro's number; there are 6.02 × 10²³ molecules in 1 mole of molecules.

$0.145 mol \times \frac{6.02 \times 10^{23}molecules }{mol} = 8.73 \times 10^{22}molecules$

NaClO₄ is a strong electrolyte that dissociates according to the following equation.

NaClO₄ ⇒ Na⁺ + ClO₄⁻

The molar ratio of NaClO₄ to Na⁺ is 1:1. The number of Na⁺ in 8.73 × 10²² molecules of NaClO₄ is:

$8.73 \times 10^{22}moleculeNaClO_4 \times \frac{1 ion Na^{+} }{1moleculeNaClO_4} = 8.73 \times 10^{22}ion Na^{+}$

The molar ratio of NaClO₄ to ClO₄⁻ is 1:1. The number of ClO₄⁻ in 8.73 × 10²² molecules of NaClO₄ is:

$8.73 \times 10^{22}moleculeNaClO_4 \times \frac{1 ion ClO_4^{-} }{1moleculeNaClO_4} = 8.73 \times 10^{22}ion ClO_4^{-}$

The molar ratio of ClO₄⁻ to Cl is 1:1. The number of Cl in 8.73 × 10²² ions of ClO₄⁻ is:

$8.73 \times 10^{22}ion ClO_4^{-} \times \frac{1 atomCl }{1ion ClO_4^{-}} = 8.73 \times 10^{22}atom Cl$

The molar ratio of ClO₄⁻ to O is 1:1. The number of O in 8.73 × 10²² ions of ClO₄⁻ is:

$8.73 \times 10^{22}ion ClO_4^{-} \times \frac{4 atomO }{1ion ClO_4^{-}} = 3.49 \times 10^{23}atom O$

17.8 g of sodium perchlorate contains 8.73 × 10²² Na⁺ ions, 8.73 × 10²² ClO₄⁻ ions, 8.73 × 10²² Cl atoms and 3.49 × 10²³ O atoms.

You can learn more Avogadro's number here: brainly.com/question/13302703

8 0

1 year ago

can you tell what the genotype of the purple flowered parent is from the information in the punnets square? explain why or why n

Nina [5.8K]

We will not be able to tell the genotype of the purple parent as it can either be a homo_zygous dominant or hetero_zygous. Without the complete genotype of the offspring, we would not be able to tell.

6 0

2 years ago