All categories

2 years ago

The arrows in the chart below represent phase transitions.

Chemistry

1 answer:

Lana71 [14]2 years ago

4 0

Answer:

a. 1,2,and 3.

Explanation:

When something turns liquid, e.g. metal, you need to heat it. When something turns gas, e.g. water, you need to heat it. And when something goes directly from solid to gas, e.g. dry ice, carbon dioxide, you need to add heat to it. hope this helps! Please mark brainiest.

You might be interested in

The compound dioxane, which is used as a solvent in various industrial processes is composed of C,H, and O atoms. Combustion of

Lady_Fox [76]

Answer:

The correct formula of dioxane is C₄H₈O₂.

Explanation:

Given data:

mass of dioxane= 2.23 g

mass of water = 1.802 g

mass of carbon dioxide = 4.401 g

molar mass of dioxane = 88.1 g / mol

Molecular formula of dioxane = ?

Solution:

percentage of carbon = (4.401 g/2.23 g ) × (12 /44) × 100

= (1.98 × 0.273) × 100 = 54.1

percentage of hydrogen = (1.802 g/ 2.23 g) × (2.016 /18.016) × 100

= (0.81 × 0.112) × 100 = 9.072

percentage of oxygen = 100 - (54.1 + 9.072)

= 100 - 63.172 = 36.828

Now we will determine the number of grams atoms of carbon, hydrogen and oxygen.

No. of gram atoms of carbon = 54.1 /12 = 4.51

No. of gram atoms of hydrogen = 9.072 / 1.008 = 9

No. of gram atoms of oxygen = 36.828 / 16 = 2.302

Atomic ratio:

C :H :O 4.51/ 2.302 : 9 / 2.302 : 2.302 /2.302

C :H :O 2 : 4 : 1

Molecular formula:

Molecular formula = n × (empirical formula)

n = molar mass of compound / empirical formula mass

empirical formula mass= 2 × 12 + 4 × 1.008 + 1 × 16

empirical formula mass= 24+ 4.032 +16 = 44.032

n = 88.1 / 44.032 = 2

Molecular formula = n × (empirical formula)

Molecular formula = 2 × (C₂H₄O)

Molecular formula = C₄H₈O₂

8 0

2 years ago

Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at

kozerog [31]

Answer:

20 g/mol

Explanation:

We can use <em>Graham’s Law of diffusion</em>:

The rate of diffusion (<em>r</em>) of a gas is inversely proportional to the square root of its molar mass (<em>M</em>).

$r = \frac{1 }{\sqrt{M}}$

If you have two gases, the ratio of their rates of diffusion is

$\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}$

Squaring both sides, we get

$(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}$

Solve for <em>M</em>₂:

$M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}$

$M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}$

$= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}$

7 0

2 years ago

How many moles in 110g of nahco3?

kenny6666 [7]

Hope this helps you.

5 0

3 years ago

If a 2.50 liter container is filled with Ne gas at a pressure of 650 mm Hg and at 25°C, what mass of Ne is in the container?

seraphim [82]

Answer:

1.76 g is the mass of Ne is in the container.

Explanation:

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 650 mm Hg

V = Volume of the gas = 2.50 L

T = Temperature of the gas = $25^oC=[25+273]K=298K$

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles of Ne gas = ?

Putting values in above equation, we get:

$650mmHg\times 2.50L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\n=\frac{650\times 2.50}{62.3637\times 298}=0.0874mol$

Also, molar mass of Ne = 20.1797 g/mol

So, $Mass = Moles\times Molar\ mass = 0.0874\times 20.1797 g = 1.76\ g$

<u>1.76 g is the mass of Ne is in the container.</u>

7 0

3 years ago

I need helppppppp plssssss

Irina-Kira [14]

Answer:

<h3>1)20</h3><h3>2)13</h3><h3>3)82</h3><h3>4)56</h3><h3>5)26</h3><h3>6)1</h3><h3>hope it helps</h3><h3>plzzz mark itas brainliest...</h3><h3> </h3><h3 />

4 0

2 years ago