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gregori [183]
3 years ago
14

5x-102=13 ( can i please be taught how to do it bc there is a lot more questions like this)

Mathematics
1 answer:
ehidna [41]3 years ago
5 0

Answer:

5*-102=13

step1 pulling out like term:1.1

pull out like factors:5x-115=5(x-23)

equation at the end of step 1 : step 2:

equation which are never true: 2.1 solve:5=0.

solve:x-23=0 solving a single variable equation

:2.2 solve :x-23=0 add 23 to both sides of the equation:x=23

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Can someone help it’s due in 40mins!!
Lorico [155]

Answer:

Step-by-step explanation:

\frac{8}{32}  =  \frac{4}{16}  =  \frac{2}{8}  =  \frac{1}{4}

\frac{27}{54}  =  \frac{9 }{18}  =  \frac{3}{6}  =  \frac{1}{2}

\frac{36}{24}  =  \frac{18}{12}  =  \frac{9}{6}  =  \frac{3}{2}

\frac{30}{60}  =  \frac{15}{30}  =  \frac{5}{10}  =  \frac{1}{2}

8 0
3 years ago
Help! how would i work this out??
Alina [70]

Answer:

i can see it

Step-by-step explanation:

6 0
3 years ago
What is the pattern in the values as the exponents increase?
nirvana33 [79]

Answer:

"Multiply the previous value by 2"

Step-by-step explanation:

Let's check the first 2 terms for all the answer choices.

1. Add \frac{1}{16} to the previous value:

\frac{1}{32}+\frac{1}{16}=\frac{3}{32}

Doesn't match.

2. Subtract \frac{1}{16} from the previous value:

\frac{1}{32}-\frac{1}{16}=-\frac{1}{32}

Doesn't match.

3. Divide the previous value by 2:

\frac{\frac{1}{32}}{2}\\=\frac{1}{32}*\frac{1}{2}=\frac{1}{64}

Doesn't match.

4. Multiply the previous value by 2:

\frac{1}{32}*2=\frac{2}{32}=\frac{1}{16}

DOES WORK!

Also, doing the same thing with all the other values would give us matching answer. So this choice is right.

7 0
3 years ago
Read 2 more answers
What did the magician do when he lost his temper?
Annette [7]
I have no idea what did he do
7 0
4 years ago
<img src="https://tex.z-dn.net/?f=-5%2B78%2B%28-32%29" id="TexFormula1" title="-5+78+(-32)" alt="-5+78+(-32)" align="absmiddle"
AysviL [449]
Adding a negative is same as subtraction
-5+78-32
73-32
41
5 0
3 years ago
Read 2 more answers
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