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3 years ago

Part of the number line is shown.

Mathematics

1 answer:

xxMikexx [17]3 years ago

8 0

Sqrt(200) is about 14
so S is the best representation for the value for sqrt(200)

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The midpoint of (-4,15) and (22,3)

ahrayia [7]

Answer:

(9, 9)

Step-by-step explanation:

midpoint of (-4,15) and (22,3)

$= \bigg( \frac{ - 4 + 22}{2}, \: \: \frac{15 + 3}{2} \bigg) \\ \\ = \bigg( \frac{18}{2}, \: \: \frac{18}{2} \bigg) \\ \\ = ( 9, \: \: 9) \\ \\$

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4 years ago

The radius of your earth model is 9cm. what is the surface area

Lapatulllka [165]

The surface area formula is 4 x pi x r^2

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3 years ago

Help please!! 15 points!!

dolphi86 [110]

15 points I got you!!!

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3 years ago

3x(x-2)-x^2+4=0<br> Help

antoniya [11.8K]

Answer:

x=2,1 solving with quadratic formula

Step-by-step explanation:

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3 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

ddd [48]

Answer:

$f'(x) = 4x^2 - 3$ for $x \le -3$

Step-by-step explanation:

See attachment for proper question

Given

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

For

$x \ge -3$

Required

Determine the inverse function

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

Replace f(x) with y

$y = -\frac{1}{2}\sqrt{x + 3}$

Swap the positions of x and y

$x = -\frac{1}{2}\sqrt{y + 3}$

Multiply both sides by -2

$-2 * x =-2 * -\frac{1}{2}\sqrt{y + 3}$

$-2x =\sqrt{y + 3}$

Square both sides

$(-2x)^2 =(\sqrt{y + 3})^2$

$4x^2 =y + 3$

Make y the subject

$y = 4x^2 - 3$

The inverse has been solved. So, we need to replace y with f'(x)

$f'(x) = 4x^2 - 3$

Next, is to determine the interval

$x \ge -3$

Change inequality to $\le$

$x \le -3$

Hence, the inverse function is:

$f'(x) = 4x^2 - 3$ for $x \le -3$

7 0

3 years ago