Answer:
20
Step-by-step explanation:
He only can put 12 boxes in 1 crate to ship 230 boxes of oatmeal the least number of crates he can use is 20 because 20 crates would= up to 240 boxes.
He can't do 19 boxes because he is short he would then only have 228 boxes and that is 2 short.
But if he does 20 crates he would be good for what needs and just have 10 more extra.
My calculations.
2 0
1 2
____
4 0
2 0 0
+
_________
2 4 0
This is saying he had 20 crates and use x as number of boxes for example each 1 crate could ship x amount of boxes and x is representing 12 boxes per crate and since he has 20 crates what is 20 x 12= x( the number of boxes total(240 boxes)
I hope this helps have a awesome day:)
The coordinates of point J' is (0,-2) which represent the image of J
let J (x,y) ⇒⇒⇒⇒ J' (x',y') = (0 , -2 )
The graph was dilated according to the rule:
(x,y) ⇒⇒⇒ ( 0.5x , 0.5y)
so, for the x coordinate
∴ x' = 0.5 x ⇒⇒⇒ x = 2x' = 2*0 = 0
for the y coordinate
y' = 0.5 y ⇒⇒⇒ y = 2y' = 2 * (-2) = -4
∴ The coordinates of J is ( 0 , -4 )
∴ The correct answer is the first option
Santiago has 87 nickles
435 ÷ 5= 87
<h3>
Answer:</h3>
System
Solution
- p = m = 5 — 5 lb peanuts and 5 lb mixture
<h3>
Step-by-step explanation:</h3>
(a) Generally, the equations of interest are one that models the total amount of mixture, and one that models the amount of one of the constituents (or the ratio of constituents). Here, there are two constituents and we are given the desired ratio, so three different equations are possible describing the constituents of the mix.
For the total amount of mix:
... p + m = 10
For the quantity of peanuts in the mix:
... p + 0.2m = 0.6·10
For the quantity of almonds in the mix:
... 0.8m = 0.4·10
For the ratio of peanuts to almonds:
... (p +0.2m)/(0.8m) = 0.60/0.40
Any two (2) of these four (4) equations will serve as a system of equations that can be used to solve for the desired quantities. I like the third one because it is a "one-step" equation.
So, your system of equations could be ...
___
(b) Dividing the second equation by 0.8 gives
... m = 5
Using the first equation to find p, we have ...
... p + 5 = 10
... p = 5
5 lb of peanuts and 5 lb of mixture are required.
These statistics compare the population density of these countries.
