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Natali5045456 [20]
3 years ago
6

Digg Co. installs a manufacturing machine in its factory at the beginning of the year at a cost of $36,000. The machine's useful

life is estimated at 10 years, or 300,000 units of product, with a $6,000 salvage value. During its first year, the machine produces 14,000 units of product. Determine the machine's first year depreciation expense under the units-of-production method.
Business
1 answer:
Nastasia [14]3 years ago
3 0

Answer:

Annual depreciation (year 1)= $1,400

Explanation:

Giving the following information:

Buying price= $36,000.

Useful units= 300,000 units of product.

Salvage value= $6,000

During its first year, the machine produces 14,000 units of product.

To calculate the depreciation expense for the first year under the units of production method, we need to use the following formula:

Annual depreciation= [(original cost - salvage value)/useful life of production in units]*units produced

Annual depreciation= [(36,000 - 6,000)/300,000]*14,000

Annual depreciation= 0.1*14,000= $1,400

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Explanation:

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The daily demand for parts from a machining workcell JMB to an assembly workcell is 1,600 units. The average processing time is
Karolina [17]

Answer:

Daily demand for parts = 1600 units

Avg processing time = 25 seconds.

Capacity of a container = 250 units

Waiting time of a container before the JMB = 6 hours

Number of containters currently deployed = 10

Solution:

Total number of parts carried by the containter = 10 x 250 = 2500 parts.

Total numbers carried in excess as safety stock = 2500-1600 = 900

Percentage of safety stock = (900/1600) x 100 = 56.25%

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Processing time at machine for 250 parts after loading in JMB = 250 x 25 seconds = 1.736 hours, but it has to wait for another 4.26 hours for the next container to be loaded because of the waiting time of the containter is 6 hours.

Processing time at machine for 1600 parts = 1600 x 25 seconds = 11.11 hours

Number of containers required for 1600 parts = 1600/250= 6.4 ~ 7 containters

Waiting time of 7 containers = 7 x 4.26 = 29.82 hours.

If one of the containers has to be removed 1600 parts has to be carried in 6 containers ie., 29.82hours - 6 hours = 23.82hours

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Reduced Total waiting time of the container = 3.97 hours + the processing time of 250 parts = 3.97 + 1.736 =5.7hours ~ 5 hours and 42 minutes

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