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jeyben [28]
3 years ago
8

1/2(2g-3)=-4(g+1) show work please do this ASAP

Mathematics
2 answers:
Neko [114]3 years ago
8 0
G=(-12) Hope this helps!
lozanna [386]3 years ago
6 0
<span><span>1/2<span>(<span>2g−3</span>)</span></span>=<span>−<span>4<span>(g+1)</span></span></span></span>
<span><span>1/2<span>(<span>2g−3</span>)</span></span>=<span>−<span>4<span>(g+1)</span></span></span></span>
<span><span>g+<span>−3/2</span></span>=<span><span>−4g</span>−4</span></span>
<span><span><span>g+<span>−3/2</span></span>+4g</span>=<span><span><span>−4g</span>−4</span>+4g</span></span><span><span>5g+<span>−32</span></span>=−4</span>
5g+−3/2+3/2=−4+3/2
<span><span>
5g</span>=<span>−5/2</span></span>
<span><span>5g/5</span>=<span><span>−52</span>5</span></span><span>
g=<span>−1<span>2

Hoped I helped!</span></span></span>
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2/3

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Question 2 of 10<br> What is the difference of the fractions below?<br> 3/4-3/5
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1 year ago
ASB is selling In-N-Out as a fundraiser. Fries cost $2 and shakes cost $3. Students can only buy one item each. ASB wants to kno
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Answer:

70 fries and 35 shakes

Step-by-step explanation:

ASB is selling In-N-Out as a fundraiser. Fries cost $2 and shakes cost $3. Students can only buy one item each. ASB wants to know which sells better but they lose track of what they sold. They know 105 students bought either fries or a shake. They count their money and it’s $245. How many fries (x) and shakes (y) did they sell?

f = fries

s = shakes

To solve this we need to make two equations. Those equations being: f+s = y and 2f+3s = y. Now we will plug in all the values. f + s = 105 and 2f + 3s = 245. Now we will subtract f from 105 to get s. this makes s =105-f. We can then plug this into the other equation making the other equation: 2f+ 3(105-f) = 245. Now we will simplify this to get: 2f + (315 -3f) = 245. When we simplify it further we get: 315-f = 245.Now we will subtract 315 from both sides to get: -f = -70. now divide both sides by -1 and we get f = 70. Now we can plug that into the f+ s = y equation. 70 + s = 105. Subtract 70 from both sides and we have s. S = 35

6 0
2 years ago
determine the value of m and n for mx^3 +20x^2+ nx-36 when divided by (x+1) gives remainder 0 and when divided by (x-2) gives re
soldi70 [24.7K]

Given:

The given polynomial is

mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0 and when divided by (x-2) gives remainder of 45.

To find:

The values of m and n.

Solution:

According to the remainder theorem, if a polynomial P(x) is divided by (x-c), then the remainder is P(c).

Let the given polynomial be P(x).

P(x)=mx^3+20x^2+nx-36

When it divided by (x+1) gives remainder 0. So, P(-1)=0.

P(-1)=m(-1)^3+20(-1)^2+n(-1)-36

0=-m+20-n-36

0=-m-n-16

m+n=-16                   ...(i)

When P(x) is divided by (x-2) gives remainder of 45. So, P(2)=0

m(2)^3+20(2)^2+n(2)-36=45

8m+80+2n-36=45

8m+2n+44=45

8m+2n=45-44

8m+2n=1                  ...(ii)

Multiply 2 on both sides of (i).

2m+2n=-32                   ...(iii)

Subtract (iii) from (ii).

6m=33

m=\dfrac{33}{6}

m=5.5

Putting m=5.5 in (i), we get

5.5+n=-16

n=-16-5.5

n=-21.5

Therefore, the values of m and n are 5.5 and -21.5 respectively.

7 0
3 years ago
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