<span><u>The answer is A. 72.25 percent.</u>
The Hardy-Weinberg principle can be used:</span>
<em>p² + 2pq + q² = 1</em> and <em>p + q = 1</em>
where <em>p</em> and <em>q</em> are the frequencies of
the alleles, and <em>p²</em>, <em>q²</em> and <em>2pq </em>are the
frequencies of the genotypes.
<span>The <em>r</em> allele (<em>q</em>) is found in 15% of the population:
q = 15% = 15/100
Thus, q = </span><span>0.15
To calculate the <em>R</em> allele frequency (<em>p</em>), the formula p + q = 1 is
used:
If p + q = 1, then p = 1 - q
p = 1 - 0.15
Thus, </span><span>p = 0.85
Knowing the frequency of the <em>R</em> allele (<em>p</em>), it is easy to determine the
frequency of the RR genotype (p²):
p² = 0.85² = 0.7225
Expressed in percentage, p² = 72.25%.</span>
~Hello there!
Your question: As an infant, the ability to produce antibodies is ________.
Your answer: As an infant, the ability to produce antibodies is limited.
Any queries?
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