Question

Which linear inequality is represented by the graph?

Answer 1

Answer:

its option B

Step-by-step explanation:

Answer 2

Answer:

$y\geq \frac{1}{3}x-1$

Step-by-step explanation:

The graph that belong to the question is attached.

Options are:

$y\geq \frac{1}{3}x-1 \\y\leq \frac{1}{3}x-1 \\y3x-1$

In the graph we observe that it's a solid line, so its equation must have symbols like $\leq ; \geq$. That only left option 1 and option 2 as possible answer.

Now, we take a test point, the easiest is $(0;0)$, that is, $x=0;y=0$. If we replace this test point in one expression and results a false statement, then that is not the answer, if result a true statement, then that's the answer.

Second expression test: $y\geq \frac{1}{3}x-1$

$0\geq \frac{1}{3}0-1\\0\geq -1$

We see that this inequality gave a true result, because zero is more than -1.

Therefore, the answer is the second option.