Question

Please help!!!!!!!!!!!!

Answer 1

Answer:

$40\frac{5}{8}mm^2$

Step-by-step explanation:

To find the area of a triangle, one must use the formula,

$\frac{base*height}{2}$

It is given that

- base = $9\frac{3}{4}$

-height = $8\frac{1}{3}$

Substitute in the values and solve;

$\frac{9\frac{3}{4}*8\frac{1}{3}}{2}$

In order to multiply the two fractions, one must convert them from mixed number form to improper fraction form. This can be done by multiplying the denominator (the number under the fraction bar), by the "number" part of the mixed number, and then adding the result to the numerator (the number over the fraction bar;

- base = $9\frac{3}{4}=\frac{(9*4)+3}{4}=\frac{36+3}{4}=\frac{39}{4}$

- height = $8\frac{1}{3}=\frac{(8*3)+1}{3}=\frac{24+1}{3}=\frac{25}{3}$

Substitute,

$\frac{\frac{39}{4}*\frac{25}{3}}{2}$

Cross simplify,

$\frac{\frac{325}{4}}{2}$

Further simplify,

$\frac{325}{4}*\frac{1}{2}\\\\= \frac{325}{8}$

Convert back to a mixed number divide the numerator by the denominator, write the whole-number result as the number outside of the fraction, and the remainder as the numerator of the fraction,

$40\frac{5}{8}$