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Sunny_sXe [5.5K]
3 years ago
14

The U.S. produces about 5.5 million tons of apples each year. Of the total, $20\%$ is mixed with other products, with $50\%$ of

the remainder used for apple juice and the other $50\%$ sold fresh. How many million tons of apples are used for apple juice? Express your answer as a decimal to the nearest tenth.
Mathematics
2 answers:
blondinia [14]3 years ago
8 0

Answer:

2.2 Million

Step-by-step explanation:

First, we wish to determine what percentage of the tons of apples are used for apple juice. After 20% is mixed with other products, 80% remains. Half of this is used for apple juice; therefore, 40% of the tons of apples is used for apple juice. To calculate 40% of 5.5 million tons, we find 10% and then multiply by four. 10% = 0.55, and 0.55* 4 = 2.2. Thus, 2.2 million tons are used for apple juice.

mars1129 [50]3 years ago
7 0

Answer:

2.2 million tons

Step-by-step explanation:

20% of 5.5 million tons is 1.1 million tons. That is how many are mixed with other products. So that would leave you 4.4 million tons of apples.

50% of 4.4 is 2.2 so 2.2 million tons are used for apple juice.

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A marine biologist monitors the population of sunfish in a small lake. He records 800 sunfish in his first year, 600 sunfish in
Colt1911 [192]

Answer:

Let's use the variable y to represent the number of years passed since the first year.

The population on the first year (y = 0) was 800

The population in the second year (y = 1) was 600.

The ratio in which the population decreased can be calculated as:

R = 600/800 = 0.75

This means that 600 is the 75% of 800, this also means that between the first year and the second year, the population decreased by the 25%

Now let's look at the ratio between the second and third year (y = 2), the population the third year was 450

Now the ratio is:

R = 450/600 = 0.75

Same as before, then we already can see that the population will decrease by 25% each year.

The generic exponential decay equation is:

f(y) = A*(1  - r)^y

where:

A = initial population, in this case, is 800

y = our variable, in this case, represents the number of years

r = the amount that decreases per each unit of our variable, this must be written in decimal form. In this case, we know that the population decreases by 25% each year, and 25% written in decimal form is 0.25

Also, (1 - r) = R, where R is the ratio we found earlier.

To do this, we just divide 25% by 100% to get (25%/100% = 0.25)

Then our equation will be:

f(y) = 800*(1 - 0.25)^y

f(y) = 800*( 0.75)^y

1) We want to predict when the population will be 200.

to do this, we set:

f(y) = 200 = 800*( 0.75)^y

and solve it for y.

(200/800) = 0.75^y

(1/4) = 0.75^y

Now we can use the relationship:

Ln(a^x) = x*ln(a)

Then let's apply Ln( ) in both sides to get

ln(1/4) = y*ln(0.75)

ln(1/4)/ln(0.75) = y = 4.8 years.

This means that 4.8 years after the first year, the population will be around 200.

2) The population in the 25 th year (this is 24 years after the first one, so we take y = 24) is:

f(24) = 800*(0.75)^(24) = 0.80

Around this point, we will have no more sunfish in the lake.

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what the number.

yaar

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450*(1+0.18)=531 hence 450 increased by 18% is 531
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