2+12a. When adding, you're only collecting "like terms".
To solve this problem you must apply the proccedure shown below:
You must switch the variables, and then, you must solve for
, as following:

Therefore, as you can see, the answer is: 
Answer:
12c square meters
Step-by-step explanation:
We know that
Area of a rectangle = length (L)× width(w)
Here it is given that length ,and width of the rectangle is 6c meters and 2 meters respectively.
Therefore, required area of the rectangle = 6c × 2 = 12c square meters.
Answer:
C. 20 feet
Step-by-step explanation:
The question has given you tan∅ = 20/50. You know that tan is opposite over adjacent. So if the opposite end is 20, that means the tree is 20 feet tall and the girl is <em>50 feet away</em>.