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svp [43]
2 years ago
9

Each grid is a part of a decimal number chart similar to the one on page how do we write the missing number

Mathematics
1 answer:
EastWind [94]2 years ago
4 0
Lol I don't knew that one srry tell some one else byeeee ohhh follow me on titter Giselle waffle lol ol Melanie 344
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Simplify the expression. 1/3r + 1/4 + 2/3r + 3/4​
expeople1 [14]

Answer:

r+1

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Help me pls only 10points
NeX [460]

y=-7x+8

y=-7x-8

-7x+8=-7x-8

8=-8

x∈∅

B. No solutions

3 0
3 years ago
Kerry has a net spendable income of $1,800 per month. She also has a significant amount of debt and payments of $150 per month.
Firdavs [7]
A the rent all together is
450 + 60 + 40 + 80 = 630
b the rent alltogether would be
500 + 50 + 40 + 70 = 660
the rent for c would cost

640 including everything
and the rent for d would be
475 + 50 + 40 + 35 = 60
so the answer would be D
hope this helped sorry for late answer
7 0
3 years ago
Is -56,912 a irrational or rational number
kow [346]
I believe it's a rational number, since it's an integer.
7 0
3 years ago
g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds
dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

The number of ways of selecting 3 cards from 13 clubs is:

{13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286

The number of ways of selecting 5 cards from 13 diamonds is:

{13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287

The number of ways of selecting 0 cards from 13 spades is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

Compute the number of ways to select 5 diamonds and 3 clubs as:

{13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0
2 years ago
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