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Ilia_Sergeevich [38]
3 years ago
10

The function f(x)=4500(0.98)^x represents the value in dollars of a vehicle x years after it has been purchased new. What is the

average decrease in value per year between years 5 and 10?
Answers:
-$78.16/year
-$3676.83/year
-0.98/year
-$4500/year
Mathematics
1 answer:
pickupchik [31]3 years ago
7 0
YEAR 5: $4067.64 -- down $432.36
YEAR 6: $3986.29 -- down $81.35
YEAR 7: $3906.57 -- down $79.72
YEAR 8: $3828.43 -- down $ 78.14
YEAR 9: $3751.87 -- down $ 76.56
YEAR 10: $3673.83 -- down $ 78.04

The average of the depreciation is $78.76 a year, so the best answer would be the first one.
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Answer:

6 units

Step-by-step explanation:

(-4 , -10) ; (-4 , -4)

Distance = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

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Answer:

1445.6 hours

Step-by-step explanation:

Distance between New York and San Francisco = 2902.8 miles (checked online)

Average speed of car = 2 mi/hr

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Time taken by Jet:

Time taken = Distance / speed

Time taken = 2902.8 / 500

Time taken = 5.8056 = 5.8 hours

Time taken by Car :

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Time taken = 5.8056 = 1451.4 hours

Time difference :

1451.4 - 5.8 = 1445.6 hours

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Step-by-step explanation:

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Use the definition f ′(x) = h0f(x + h) - f(x)h to find the derivative. f(x)=x+2
NNADVOKAT [17]

Answer:

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General Formulas and Concepts:

<u>Calculus</u>

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Step-by-step explanation:

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f(x) = x + 2

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  2. Distribute:                          f'(x)= \lim_{h \to 0} \frac{x + h + 2-x-2}{h}
  3. Combine like terms:         f'(x)= \lim_{h \to 0} \frac{h}{h}
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