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andrew11 [14]
3 years ago
14

What’s the missing side length of that question

Mathematics
2 answers:
Andrew [12]3 years ago
8 0
It looks like the Pythagorean theorem so
a^2+b^2=c^2
4^2*b^2=7^2
16+b^2=49
49-16=33
Square root of 33 rounded is 5.74
So I think the answer is 5.74
omeli [17]3 years ago
4 0

Answer:

answer: the missing side is 5

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What is (f - g)(x)?<br> f(x) = -2x + 4<br> g(x) = -x2 + 4x + 5
kipiarov [429]

Step-by-step explanation:

( - 2x + 4) - ( - {x}^{2}  + 4x + 5) =    {x }^{2}  - 6x - 1

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3 years ago
For the function f(x) = x^2+ 3, what are the outputs for the inputs -3, 2, 0, and 5?
AysviL [449]

Answer:

F(-3)=12

F(2)=7

F(0)=3

F(5)=28

Step-by-step explanation:

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Write<br> 17/3<br> as a mixed number.<br> O A. 3<br> O-B. 3<br> © C.53<br> O D. 53
IRINA_888 [86]

Answer:

5 2/3

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15 ÷ 3 = 5.

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5 + 2/3 = 5 2/3

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3 0
3 years ago
Read 2 more answers
What’s the midpoint of the line segment joining A and B<br><br> A(2,-5);B(6,1)
IRISSAK [1]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{2}~,~\stackrel{y_1}{-5})\qquad B(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{6+2}{2}~~,~~\cfrac{1-5}{2} \right)\implies \left( \cfrac{8}{4}~,~\cfrac{-4}{2} \right)\implies (4,-2)

7 0
3 years ago
On any given day, the probability that a large local river is polluted by carbon tetrachloride is 0.12. Each day, a test is cond
babymother [125]

Answer:

a) 0.2416

b) 0.4172

c) 0.0253

Step-by-step explanation:

Since the result of the test should be independent of the time , then the that the test number of times that test proves correct is independent of the days the river is correct .

denoting event a A=the test proves correct and B=the river is polluted

a) the test indicates pollution when

- the river is polluted and the test is correct

- the river is not polluted and the test fails

then

P(test indicates pollution)= P(A)*P(B)+ (1-P(A))*(1-P(B)) = 0.12*0.84+0.88*0.16 = 0.2416

b) according to Bayes

P(A∩B)= P(A/B)*P(B) → P(A/B)=P(A∩B)/P(B)

then

P(pollution exists/test indicates pollution)=P(A∩B)/P(B) = 0.84*0.12 / 0.2416 = 0.4172

c) since

P(test indicates no pollution)= P(A)*(1-P(B))+ (1-P(A))*P(B) = 0.84*0.88+  0.16*0.12 = 0.7584

the rate of false positives is

P(river is polluted/test indicates no pollution) = 0.12*0.16 / 0.7584 = 0.0253

4 0
3 years ago
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