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Setler [38]
3 years ago
15

Which of the following equations are not balanced​

Chemistry
2 answers:
Mandarinka [93]3 years ago
6 0
The answer is the third one which is C
geniusboy [140]3 years ago
4 0
2nd one is the correct answer
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The isotope tritium has a half-life of 12. 3 y. Assume we have 11 kg of the substance. How much tritium will be left after 51 y?
Mama L [17]

Half-life is a time in which the concentration of the substance gets reduced to 50% of the initial concentration. The number of tritium that will be left after 51 years is 0.624 kg.

<h3>What is an isotope?</h3>

Isotopes are chemical substances that have the same atomic number but different atomic mass because they have a different number of neutrons in the nuclei.

The half-life of the isotope, tritium is 12.3 years. Assuming we have 11 kg of substance and a number of years 51 years.

11 \times 2 ^{\frac{-51}{12.3}} = 0.6239 \;\rm kg

Therefore, the number of tritium that will be left after 51 years is 0.624 kg.

Learn more about half-life here:

brainly.com/question/17018072

#SPJ4

7 0
2 years ago
Suppose that 98.0g of a non electrolyte is dissolved in 1.00kg of water. The freezing point of this solution is found to be -0.4
Sholpan [36]

Answer:

\large \boxed{\text{392 u}}

Explanation:

1. Calculate the molal concentration

The formula for the freezing point depression by a nonelectrolyte is

\Delta T_{f} = -K_{f}b\\b = -\dfrac{\Delta T_{f}}{ K_{f}} = -\dfrac{-0.465 \, ^{\circ}\text{C}}{\text{1.86 $\, ^{\circ}$C$\cdot$kg$\cdot$mol}^{-1}} = \text{0.250 mol/kg}

2. Calculate the moles of solute

\begin{array}{rcl}b & = & \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\\text{moles of solute} & = & b \times {\text{kilograms of solvent}}\\n & = &\text{0.250 mol/kg} \times \text{1.00 kg}\\ & = & \text{0.250 mol}\\\end{array}

3. Calculate the molecular mass

\begin{array}{rcl}\text{Moles} & = &\dfrac{\text{mass}}{\text{molar mass}}\\\\\text{0.250 mol} & = & \dfrac{\text{98.0 g}}{MM}\\\\MM & = & \dfrac{\text{98.0 g }}{\text{0.250 mol}}\\\\& = &\textbf{392 g/mol}\\\end{array}\\\text{The molecular mass of the solute is $\large \boxed{\textbf{392 u}}$}

3 0
4 years ago
For which of the following reactions will the reactant experience the largest degree of decomposition
ASHA 777 [7]

Answer:

D) 2 NOCl(g) ⇄ 2 NO(g) + Cl₂(g); Kp = 1.7 × 10⁻²

Explanation:

In order to compare the degree of decomposition of these reactions, we have to compare the equilibrium constant Kp. Kp is equal to the partial pressure of the products raised to their stoichiometric coefficients divided by the partial pressure of the reactants raised to their stoichiometric coefficients. The higher the Kp, the more products and fewer reactants at equilibrium. Among these reactions, D is the one that has the highest Kp, therefore the one experiencing the largest degree of decomposition.

4 0
4 years ago
Which compound is an exception to the octet rule
anyanavicka [17]

I think it's RbCl and CaO
7 0
4 years ago
When 11.2 liters of hydrogen gas is made by adding zinc to sulfuric acid, what mass
IgorC [24]

32.7 g Zn

Explanation:

First convert the amount of gas into moles:

11.2 L H2 × (1 mol H2/22.4 L H2) = 0.500 mol H2

Then use the molar ratio to find the amount of zinc necessary to produce the amount of gas above:

0.500 mol H2 × (1 mol Zn/1 mol H2)

= 0.500 mol Zn

Now use the molar mass of zinc to find the number of grams of zinc for the reaction to occur:

0.500 mol Zn × (65.38 g Zn/1 mol Zn)

= 32.7 g Zn

7 0
3 years ago
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